14D_f11_e02

14D_f11_e02 - Chemistry 14D Fall 2011 Exam 2 Page 1...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chemistry 14D Fall 2011 Exam 2 Page 1 Page 1 score = Questions 1–4 refer to the reaction of styrene (PhCH=CH 2 ) with an aqueous mixture of nitric and sulfuric acids, shown below. aq. HONO 2 aq. H 2 SO 4 NO 2 + OH + OH Styrene Molecule A Molecule B Molecule C 1. (9) Only one product is produced in any significant amount. For each molecule listed below circle 'is' or 'is not', as appropriate. If you circled 'is' you are done for this molecule. If you circled 'is not' complete the statement by adding no more than twenty words . Molecule A is / is not the major product because. .. Molecule B is / is not the major product because. .. Molecule C is / is not the major product because. .. 2. (6) Write a complete mechanism for the conversion of styrene into molecule B . Do not assume that just because you are asked to write this mechanism that molecule B is the major product . 3. (3) The reaction of styrene with aqueous HONO 2 and aqueous H 2 SO 4 provides an additional product of molecular formula C 16 H 18 O. Consider the mechanism you wrote in question 2, then draw in the box a reasonable structure for this additional product. 4. (2) Circle the molecule that reacts fastest with aqueous HONO 2 and aqueous H 2 SO 4 .
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/12/2012 for the course CHEM 14D taught by Professor Hardinger during the Winter '08 term at UCLA.

Page1 / 5

14D_f11_e02 - Chemistry 14D Fall 2011 Exam 2 Page 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online