14D_w09_e02_key

14D_w09_e02_key - Chemistry 14D Winter 2009 Exam 2...

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Chemistry 14D Winter 2009 Exam 2 Solutions Page 1 Statistics : High score, average, and low score will be posted on the course web site after exam grading is complete. The exam is ready to be picked up when these numbers are posted. Some questions have more than one answer, even though only one answer may be listed here. To see the projected course grade cutoffs, consult the grading scale on the Chemistry 14D course web page. 1. (a) Syn (b) Anti-Markovnikov 2. Many answers are acceptable, as long as they correctly illustrate the syn, anti-Markovnikov addition of water to an alkene or alkyne, with the correct reactants. For example: 3. Molecule C 4. 5. This is expected to be the major reaction product because the hydrogen abstraction step of this mechanism leads to a more stable radical intermediate than the hydrogen abstraction step of the mechanism leading to molecule B . 6. 7. Molecule D Molecule E 8. D E The alkyne of molecule A does not have a C–H bond, so Markovnikov’s Rule does not apply
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This note was uploaded on 03/12/2012 for the course CHEM 14D taught by Professor Hardinger during the Winter '08 term at UCLA.

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14D_w09_e02_key - Chemistry 14D Winter 2009 Exam 2...

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