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Unformatted text preview: nclosed between the line y = −3 and the curve y = 2x − x2.
First we ﬁnd the points where the line and the curve intersect.
−3 = 2x − x2
x2 − 2x − 3 = 0
(x − 3)(x + 1) = 0 So the points of intersection occur at x = 3 and x = −1.
Now we need to determine whether the line or the curve has greater values on the entire interval (−1, 3). To do this, we evaluate both expressions at point in the interval; for simplicity
we pick x = 0. For the line we have a y-value of −3, and for the curve we have a y-value...
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This note was uploaded on 03/01/2012 for the course MATH 1110 at Cornell.