ECE 231 -2

# ECE 231 -2 - ECE-231 Circuits and Systems I Fall 2011...

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ECE-231 Circuits and Systems I Fall 2011 Session 2 Dr. Stewart Personick Office: ECEC Room 331 [email protected]

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Controlled Sources
5000 i2 node e 0.1 volt (voltage source) i3 node b - + 2500 7500 node a node c Controlled current source: i = β x i2 example: β = 100 Controlled Sources: Current controlled Current Source

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5000 i2 node e 0.1 volt (voltage source) i3 node b - + 7500 node a node c Controlled current source: i = β x i2 example: β = 100 Controlled Sources: Current controlled Current Source KCL: i5 - i2 =0 amperes 2 equations and 2 unknowns 7500 x i5 + 2500 x i2 - 0.1V = 0 volts Therefore: i2 = 0.1 volts /(7500 + 2500 ) = 0.00001 amperes = 10 microamperes i5 2500
i2 node e 0.1 volt (voltage source) node b - + 7500 node a i3 5000 node c Controlled current source: i = β x i2 example: β = 100 Controlled Sources: Current controlled Current Source i2 = 0.1 volts /(7500 + 2500 ) = 0.00001 amperes = 10 microamperes i= 100 x i2 ; i3 + i = 0 amperes Therefore: i3 = -100 x 10 microamperes= -1mA 2500

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Controlled Sources: Current controlled Current Source i2 node e 0.1 volt (voltage source) node b - + 7500 node a 5000 node c Controlled current source: i = β x i2 example: β = 100 i3 = -1 milliampere vce = i3 x 5000 = -5 volts i3 2500
Controlled Sources: Current controlled Current Source i2 node e 0.1 volt (voltage source) node b - + 7500 node a 5000 node c Controlled current source: i = β x i2 example: β = 100 vce = -5 volts The application of a 0.1 volt “input voltage” (between node a and node e) results in a -5 volt “output voltage” (between node c and node e). The circuit produces a “voltage amplification ratio” of: -50, between it’s input and its output . 2500 i3

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Transistor circuit (grounded emitter) b c e - + 10000 ( power supply feeder resistance) 7500 10000 (input resistance of the next amplifier stage) To voltage source (power supply) i2 -i6 -i4 The collector current (-i6- i4) = β x the base current (i2 + i1). A typical value of β = 100 To base “bias” current source i1 vs Input signal Output signal
node e 0.1 volt (voltage source) node b - + 5000 node a 5000 node c Controlled voltage source: v = 100 vae + - i1 Controlled Sources: Voltage controlled Voltage Source

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node e 0.1 volt (voltage source) node b - + 5000 node a 5000 node c Controlled voltage source: v = 100 vae + - i1 i1 = -99 x 0.1 volts / 10000 ohms = -0.00099 amperes KVL: 5000 x i1 + 5000 x i1 + 100vae - vae = 0 vae = 0.1 volt Two (2) equations and two (2) unknowns Controlled Sources: Voltage controlled Voltage Source
voltage from + to - on its control voltage terminals. [Edit => Component=> e]

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## This note was uploaded on 03/01/2012 for the course ECE 231 taught by Professor Pietrucha during the Spring '08 term at NJIT.

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ECE 231 -2 - ECE-231 Circuits and Systems I Fall 2011...

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