{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ECE 231 -6

# ECE 231 -6 - ECE-231 Circuits and Systems I Fall 2011...

This preview shows pages 1–10. Sign up to view the full content.

ECE-231 Circuits and Systems I Fall 2011 Session 6 Dr. Stewart Personick Office: ECEC Room 331 [email protected]

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
New Materials Energy Storage Components Capacitors Inductors Voltage sources and current sources whose values vary with time: v(t), i(t) Circuits that incorporate time varying sources, resistors, capacitors, and inductors
Mechanical Analogy A ball on a half pipe: Starts (as shown) with only stored potential energy: E= G x m x h h

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Mechanical Analogy A ball on a half pipe: Starts (as shown) with only stored potential energy: E= G x m x h Transitions to only stored kinetic energy: E= ½ mvmax2 h vmax
Mechanical Analogy A ball on a half pipe: Starts (as shown) with only stored potential energy: E= G x m x h Transitions to only stored kinetic energy: E= ½ mvmax2 Then transitions to only stored potential energy: E= G x m x h h

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Mechanical Analogy A ball on a half pipe: At any point in between, the energy of the ball is: E= G x m x h(t) + ½ m v2(t) h
Mechanical Analogy A ball on a half pipe: At any point in between, the energy of the ball is: E= G x m x h(t ) + ½ m v2(t) = a constant value of energy If the half-pipe has a parabolic shape, where h= bz2 Then: E = G x m x b x z2(t) + ½ m v2(t) h z=0 z z=(h/b)0.5

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Network component: Capacitor Capacitance = C (Farads) a b A capacitor consists of a pair of parallel plates, which have area A (m2) and spacing d (m)
Network component: Capacitor Capacitance = C (Farads) - e - e - e - e e e e e e =the electron charge = -1.6 x 10-19 Coulombs The voltage across the capacitor that results from the presence of the charge on the plates is Vab = Q/C. where: Q is the charge, in Coulombs on the left plate [= - the charge, in Coulombs, on the right plate]; and C is the capacitance of the capacitor (Farads) From physics: C is approximately: the plate area/the plate spacing x ε r x ε 0 Where: ε 0 is the electric constant ( ε 0 ≈ 8.854×10−12 F m–1), and

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 30

ECE 231 -6 - ECE-231 Circuits and Systems I Fall 2011...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online