ECE 231 -14

ECE 231 -14 - ECE-231 Circuits and Systems I Fall 2011...

This preview shows pages 1–11. Sign up to view the full content.

ECE-231 Circuits and Systems I Fall 2011 Session 14 Dr. Stewart Personick Office: ECEC Room 331 [email protected]

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Review
Review: Solving for the Dependent Currents and Voltages in DC circuits

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The objective is to use Kirchhoff’s Laws, Ohm’s Law, and the information you are given regarding the values of the independent sources, the resistors, etc. to produce a set of equations that can be used to solve for the unknown (dependent) currents and voltages in a circuit
The Mesh Current Method 500 node e Vah= 50 volts (voltage source) node b - + 1000 500 Controlled voltage source: Vde= 500 V/A x i2 500 node d i1 i2 i3 + - Mesh 2 has only a resistor or a wire (0 Ohm resistor) in every branch Therefore, using Kirchoff’s voltage law, we add the voltages in a closed path around mesh 2, starting at node b: Vbc + Vcf +Vfg +Vgb =0 Volts 0 + 500 (i2 - i3) + 0 + 1000 (i2 - i1) = 0 Volts node c node a node f node g node h Vah

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The Mesh Current Method 500 node e Vah= 50 Volts (voltage source) node b - + 1000 500 Controlled voltage source: Vde= 500 V/A x i2 500 node d i1 i2 i3 + - Mesh 1 has a resistor or a wire (0 Ohm resistor) or a voltage source in every branch Therefore, using Kirchoff’s voltage law, we add the voltages in a closed path around mesh 2, starting at node a: Vab + Vbg + Vgh + Vha =0 Volts 500 (i1) + 1000 (i1 - i2) + 0 -50 Volts = 0 Volts node c node a node f node g node h Vah
The Mesh Current Method 500 node e Vah= 50 Volts (voltage source) node b - + 1000 500 Controlled voltage source: Vde= 500 V/A x i2 500 node d i1 i2 i3 + - Mesh 3 has a resistor or a wire (0 Ohm resistor) or a voltage source in every branch Therefore, using Kirchoff’s voltage law, we add the voltages in a closed path around mesh 2, starting at node c: Vcd + Vde + Vef + Vfc =0 Volts 500 (i3) + 500 V/A x i2 + 0 + 500 (i3 - i2) = 0 Volts node c node a node f node g node h Vah

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The Mesh Current Method 500 node e Vah= 50 Volts (voltage source) node b - + 1000 500 Controlled current source: i = 5 x i2 500 node d i1 i2 i3 Mesh 3 has a resistor or a wire (0 Ohm resistor) or a current source in every branch The branch current in the branch containing the current source is completely determined by the current source In this example , the branch current in branch e-d is: 5 x i2 This branch current is equal to -1 x the mesh current in mesh 3. i3 = -5 x i2 node c node a node f node g node h Vah
The Mesh Current Method 500 node e is= 2 Amperes (current source) node b 1000 500 500 node d i1 i2 i3 Mesh 1 has a resistor or a wire (0 Ohm resistor) or a current source in every branch The branch current in the branch containing the current source is completely determined by the current source In this example , the branch current in branch h-a is: 2 Amperes This branch current is equal to the mesh current in mesh 1. i1 = 2 Amperes node c node a node f node g node h is Controlled voltage source: Vde= 500 V/A x i2 + -

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The Node Voltage Method 500 node f Vah= 50 volts (voltage source) node b - + 1000 500 Controlled voltage source: Vcf = 500 V/A x ibg 500 node c + - The voltage at node g is defined as 0 Volts [Node g has been selected
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/01/2012 for the course ECE 231 taught by Professor Pietrucha during the Spring '08 term at NJIT.

Page1 / 62

ECE 231 -14 - ECE-231 Circuits and Systems I Fall 2011...

This preview shows document pages 1 - 11. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online