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Unformatted text preview: 7:67,. 3 Anf/UL» goof 1 Consider a simpIe circuit in which a capacitor is discharging through a resistor. If you multiply the capacitance of the capacitor by the resistance of the resistor, the quantity you obtain is .
CA: the maximum voltage that appears acrOSS the capacitor.
C: B =3 the time required for the charge on the capacitor to reduce to 1/ e of its originalvaluen/l
:: C: the ﬁnal value of the current through the resistor. ‘ (Y‘. ‘2' Cr #0 r {ac Ore r ‘L
I: D 3 the initial value of the current through the resistor. ‘x  " v
R 1.. c m w’r lIE:I thehnpedanccofthecircuit. X ‘1‘ : ‘7‘: In organizing his four equation of electromagnetism. Maxwell introduced a quantity that did not appear in previous
physical laws dealing with electromagnetism. That quantity is ' C A:l electric ﬂux. C 33 magnetic ﬂux. I: C: permittivity of vacuum.
1: D3 permeability of vacuum. I: E I! displacement current. \/ 3 The magnitude of the Poyming vector of an electromagnetic wave is equal to I: A5 the intensity of the Wave. I: B: the momentum carried by the wave. \ﬂ
C C:1 the wavelength of the wave. E D3 the frequency of the wave. I: E =1 the velocity of the wave. \l 4 When an object is placed 30.0 cm in front of a certain thin lens, an image is formed on the same side of the lens as the object. The distance from the lens to the image is 40.0 cm. Is the lens a converging or diverging lens? What is
the absolute value of its focal length? ' ' ' ' CA3 converging lens. 17.1 cm I ' nL
:B‘J diverging lens, 17.1 cm " i; Q EC: converging lens. 120 cm E D3 diverging lens, 120 cm E E3 None of the above A certain sinusoidal electromagnetic wave in vacuum produces a maximum magnetic induction of 5.00 X 10‘12 T.
What is the maximum electric ﬁeld intensity produced by the wave? _=A= 5.00 x IO‘” Vim :3: 1.50 x 103 Vim v’
cc: 1.67 x 1020 we
to: 8.66 x 103 Vim E E:I None of the above 6 '10 \ When a 4.00—cmtall object is placed 30.0 cm in front of a certain concave (converging) spherical mirror, a real
inverted image is formed on the same side of the mirror as the object. The distance from the mirror to the image is
20.0 cm. What is the absolute value of the height of the image? ’ CA3 15.0cm M F ._, .1 2"”
:3: 12.0m ' f "w 13"“: i
E03 9.00 cm lg to: 2.67cm/ a, X 0.185] ; C E 3 None of the above An ac current of frequency 2000 Hz ﬂows through a 3.00 X 10‘5F capacitor. What is the reactance of the capaci tor? _.
CB: 0.0377 n X C ”' M C tcz coax 10—30 ) 7_ :D: 167 Q 3 E E =1 None of the above A circuit contains an ac generator, 3 3.09 X 10—512 capacitor, and a 2.00 X 10‘311 inductor, all in series. The
emf of the generator has constant amplitude. At what generator frequency does maximum current ﬂow through the
circuit; i.e., what is the resonance frequency of the circuit? r EA: 6.00x109Hz— a) stir”: : w; :BTJ 7:st 105Hz . r: . " r“
I P; __.r . 1 £4 \ :0: 2.05 x 103 Hz
to: 1.29 x 104 Hz
E E 2' None of the above The index of refraction of a certain type of glass for a certain wavelength of light is I What is the speed of light
in that glass forthat particular wavelength? CA:1 4.50 X 103 mls
I: B:1 7.85 X 106 mils
cc: 1.15 x 1010 mls
I=D= max 103 rule \4’
CE: None of the above A moth at about eye level is 15.0 cm in front of a plane mirror; you are behind the moth, 60.0 cm from the mirror.
For what distance must you focus your eyes to see the image of the moth in the mirror; that is, what is the distance between your eyes and the apparent position of the image? a
a s EA: 120cm I=B= 90.0 cm cc: 75.0cm/ [do 4 1? ED:1 45.0cm #i‘ its 7!: E:I None of the above ‘ 'Wst 5  417’” 2005 ® 3 ’t;?\C 4;. semis
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' V W" of 4W «~ We’re»... @ art4527f“. PHYS 202 (Sec. 1) TEST 3 November 3, 2005 INSTRUCTIONS NOTE: YOU LOSE 5 POINTS IF YOU FAIL TO FOLLOW ANY OF THESE INSTRUCTIONS. 1.
2.
3. Answer this test on the furnished SCANTRON card (or its equivalent) using a #2 pencil.
In the blank labeled “NAME” on the SCANTRON card, print your name. Read the directions in the box labeled “IMPORTANT” on the SCANTRON card. Note that you must erase
pencil marks cornpletely when changing your entries. Following the instructions in the box labeled “PART 1" on the SCANTRON card, write your nine~digit ID
number in the appropriate spaces, starting at the top row. Code your ID by marking through the correct numbers
as instructed. The bottom row in the ID box should be left empty. Each question in the attached test has a corresponding row on the SCANTRON labeled by the question numbers
“1 ", etc. Mark through the letter on the SCANTRON card corresponding to your answer for that question.
You lose 10 points for each question in which you mark a wrong answer, no answer, or more than one answer.
In numerical problems, mark an answer if it is within 10% of your answer. When you are through, double check your marks and erasures! Also, be certain your answers are in the rows
corresponding to the question numbers on the test. Turn in only the SCANTRON card. 1 We have said that the speed of an electromagnetic wave in vacuum equals its frequency multiplied by its wave
length. Thus, if you double the frequency of such a wave, you must
IZAII double its intensity. / n rSB:I double its speed. I '1
:CZI reduce its speed by one half. I2D:J double its wavelength. @educe its wavelength by one half. 2 In an electromagnetic ﬁeld in vacuum, the cross product of the electric ﬁeld intensity and the magnetic induction
divided by the permeability of vacuum is EAII the energy density. E33 Maxwell’s displacement current.
I263 the Poyntin g vector. lID:I the momentum carried by the ﬁelds. E E II the reactance. 3 Suppose you have a lens which is convex (bulging out at the center) on both sides. You could increase its focal
length by <EE‘Ejhcreasing the radius of curvature of both sides. f .
EB:l decreasing the radius of curvature of only the side on which the light enters. t '
ECII decreasing the radius of curvature of only the side on which the light leaves. C D3 decreasing the radius of curvature of both sides. E E 3 increasing the index of refraction of the material from which the lens is made. 4 A sinusoidal ac current of amplitude 3.00 A and frequency 500 Hz ﬂows through a 2.00 H inductance. What is
the amplitude of the ac potential difference across the inductance? :A: aopv / \ v = I: 0
“£63 4.77 x 10'4v \/ 5 t5) BOOM 7/» ( 7’17) CD: 1.91 x 103 V
3 one of the above
5 An ideal parallel plate capacitor consists of horizontal plates, each of area 3.00 X 10‘3 m2, separated by vacuum. The vertical electric ﬁeld in the plates at time t is E = 900 MC — (2000 Nsleh‘z, where positive E is upward.
At time: = 0.500 s, what are the magnitude and direction of the displacement current between the plates? EAj 5.31 X 10‘” A upward ,
' \ . .I I.
"(932)53] X 10‘“ A downward J; ‘_ d 0:) “Z . L110: )0 L ECII 1.06 X 10‘” A upward _ J
‘4 s 3 DOWN M
ED3 1.06 X 10‘” A downward
I: E 3 None of the above f I 
'/ Mn” ric’s 1‘ , . 6 A 4000!) resistance in series with an uncharged 8.00 X 10‘5F capacitance are suddenly connected to a 12.0‘V
battery. How much charge is on the capacitor 6.00 X 10'2 s later? (EA: .13 x 105 c 5 "En—i '1 : HOOD ‘l‘ 31* ' g CB: 1.47>< 10 c Sam . g t M
cc: 9.60X 105c n»! 1
ED: 5.12>< 105 c ~ ‘ 32M 12, s “00022; i 3 ' H ': C'VL
ﬂow of the above “ “"'*”rj q) H _ l I I 7 An object is placed 40.0 cm in front of a converging (concave) mirror with focal length 30.0 cm. Where is the
image formed? CA3 17.1 cm behind the mirror
f6 17.1 cm in front of the mirror I I. I; / I I ' A ’ 4 1’”
(I: I 0 cm behind the mirror I; O :5 g, r)
@213 cm in front of the mirror 0'"! 2' L CE II None of the above 8 A black, totally absorbing piece of cardboard intercepts light with an intensity of 0.500 W/mz. Assuming
the incident beam is perpendicular to the plane of the cardboard, what radiation pressure is produced on the cardboard by the light? @267 x 10"9 Pa i=3: 1.50 x 108 Pa
@442 x 10—12 Pa
EDII 5.98 X 105 Pa
C E =1 None of the above
9 A certain circuit consists of resistances, capacitances, and inductances. When the sinusoidal ac voltage across it has an rms value of 5.00 V. the rms current is 4.00 A. If the phase difference between the voltage and current is
30.0”, what average power does the circuit dissipate? EA: 600 W
5 c321 "13.3 w
'ECS 69.3 w
CD3 10.0w
lIE:I None of the above 10 A ray of light from the sun strikes the surface of a liquid at an angle of 600° from vertical. The ray in the liquid
is at an angle of 200° from vertical. What is the index‘of refraction of the liquid? EAZ' 0.667 .3 ..
J ' '33:' 0.395 ’ C) "‘7? ‘ ‘21)
6932.53 .. 2’ A 1):) if I” “ *'‘ ' rw IA. ' v I 13w 2 0
ﬁg one of the above /20“ ﬂ”
/ f n f g f. '_z_(> D ' 27%» I 0'32”? SCRATCH SHEET Information you may or may not need: gravitational acceleration near earth = 9.80 I'll/82
absolute value of electronic charge = 1.60 X 10‘19 C
rest mass of electron = 9.11 X 10‘31 kg rest mass of proton = 1.67 X 10'27 kg permittivity of vacuum = 8.85 X 10‘12 F/m 5:;
permeability of vacuum = 427 X 10—7 TIn/A ﬂy
speed of light in vacuum = 3.00 X 108 mfs L
proportionality constant for Rayleigh criterion for resolution for circular aperture = 1.220
Planck’s constant: 6.63 X 10—34 Js
StefanBoltzmann constant = 5.67 X 10‘3 W/(m2K4)
ﬁrst Bohr radius in hydrogen = 5.29 X 10‘ll m
ground state energy in hydrogen = — 13.6 eV 1 curie = 3.7 X 1010 decays/s 19L: H000; 7' [as'OOOrS . . .. . ..L i U ' (I) a"
. ,. .300 ’ Ms 6 a i 7) L D [)6 g}. L r ll‘SOOO M (r0000 w 7‘;{.X_)r0 IIIOOUZ‘) if) 7;. g€”(_)c) @ ciw‘z 1 When an object is placed 30.0 cm in front of a certain thin lens. an image is formed on the same side of the lens
as the object. The distance from the lens to the image is 40.0 cm. Is the lens a converging or diverging lens? What is the absolute value of its focal length? 10333537I9 EA: converging lens. 17.1 cm
*diverging lens. 17.1 cm 9:2 E E 3 None of the above corwerging lens. 120 cm
diverging lens, 120 cm 2 Consider a simple circuit in which a capacitor is discharging through a resistor. If y0u multiply the capacitance of the capacitor by the resistance of the resistor, the quantity you obtain is ' _ + J
cA: the maximum voltage that appears across the capacitor. 5\ a; (k te Q“
IB the time required for the charge on the capacitor to reduce to l/e of its original value. Q m g fig“
:0: the ﬁnal value of the current through the resistor. V ,_—_ VQ T. IID =1 the initial value of the current through the resistor.
CE :1 the impedance of the circuit. Warm” 3 A certain sinusoidal electromagnetic wave in vacuum produces a maximum magnetic induction of
5.00 x 10“2 T. What is the maximum electric ﬁeld intensity produced by the wave? CA3 5.00 X 10''2 Vim
QI l.50 X 10"3 Vim
I=02! _i.67 X 10'20 Vim
EDD 8.66 X 10'3 Vim
EEII None of the above am a (a w)
. faicg megawatt 4 When a 400cmtall object is placed 30.0 cm in front of a certain concave (converging) spherical mirror, a real
inverted image is formed on the same side of the mirror as the object. The distance from the mirror to the image is 20.0 cm. What is the absolute value of the height of the image? L f C Q 3
:A: 15.0cm I L  I p ‘6 " 2' {ﬂ
/ + __ H ‘C :3: 12.0 cm P (h H l
C a 91m v'—  en‘uﬁ .._ _..,._ _‘__ ___. —MH———‘'—'L~ c “n as Jim. 1 l ,
.3. 2.67 cm _ g «a. f ..____... ...._ :
cEzl' None ofthe above P 3: 3 O “‘13 30 5 In organizing his four equation of electromagnetism, Maxwell introduced a quantity that did not appear in
previous physical laws dealing with electromagnetism. That quantity is CA: electric ﬂux. '2 B 2' magnetic ﬂux. C03 permittivity of vacuum:
CD =1 permeability of vacuum. =5 displacement current. 6 An ac current of frequency 2000 Hz ﬂows through a 3.00 X 10'5F capacitor. What is the reactan‘ce of the (agitator?
CA 26.5.0 \ X C C ,t
[1‘ ' EB: 0,0377“ 7) “Q g cc: 6.00 x 103 n 1‘
s so: 1670: ' _ ,5 f 20% * None of the above C '73 ’30 ﬁg“ The magnitude of the Ploynting vector of an electromagnetic wave is equal to
I!“ the intensity of the wave. CB :1 the momentum carried by the wave. 7’ CC :1 the wavelength of the wave. 7 {a CD: the frequency of the wave. / ’/ cl 9 E :’ E
37.33 73 ’3" CE: the velocity of the wave. a. 2 _ .s B A circuit contains an ac. generator, a 3.00 X 10‘6F capacitor. and a 2.00 x 10“ H inductor. all in series. The
emf of the generator has constant amplitude. At' what‘generator frequency'd\maxiinum current ﬂow through
the circuit; i.e., what is the resonance frequency of the circuit? 7    :A:6.00x109Hz , . ' “‘_ r ' " ’M / ’ / ﬁg f a; C 2 To“: vim _ 'cB: 7.75X10'5Hz @zm' ' I 1.29 x10‘m... _ '—‘E=I Noneoftheaboveayé . 4 I I'_ ’ y r 2:43 _  x . 1 j ﬂ re. 5 ﬁ‘sﬂ» f” C . i _ ,_.« 7 7  .H l'
‘ A + 9 The index of refraction of a certain type of glass for a certain wavelength of light is 1.50. What is the speed of
' light in that glass for that particular wavelength? _ C
:A: 4.50 X 10’5 mls X : H ' _
:3: 7.85 x 10‘5 m/s 4 3‘9 ﬂ "' l/ ' C ‘ ' cc: 1.15X10'0mls 3%  ‘. Am
_ _ f. 1.
ale2.00mst ‘C [50 Vm 4 C; I” ’ 0
CE: None of the above. ' a " A moth at about eye level is 15.0 cm in front of a plane mirror; you are behind the moth. 60.0 cm from the
mirror. For what distance must you focus your eyes to see the image of the moth in the mirror; that. is. what is
the distance between your eyes and the apparent position of the image? CA3 120 cm
1" 90.0 cm ‘ :.0 cm f :D: 45.0 cm lIE 3 None of the above '23., // 0641 3 “‘7‘; may? >4 Before the switch below is closed. there is a charge of 3.00 EC on the capacitor. How much charge is on the capacitor 5.00 x 103 s after the switch is closed?  397%; 54w; a  ‘i‘e‘ff‘
EA: l.53,ttC rut \ '_
4.00 arl ' ~—i
l2C2I 4.69 [1C : Q KC
soon Q _ (5 Mo": E 3 : 3 / __ _ . CE 3 None of the above* 2 The equation relating the directions of the hymn? and the retractedray‘when light leaves One medium and
enters another is known as I=A=J Poymtitlg's law. ssthaISasﬂ‘ifTi‘i?» I/z 0 0y (6* X "0 “é cc: the as oftotaiime‘mal reﬂection. Q 5 70 00 a
CD: the law ofﬁi’fergence. I "
CE = Maxwellldisplaoement law. 5 " n w The current i(t) ﬂowing through a (moH inductance at time: is given by \ g t I _ f I
s i(t) = (3.00 A)sin[(4000 313:]. ‘ Q..ifff_£‘fff5 ' s 3 ‘Ws ' o ,
v mu m What is the absolute value of the voltage drop across the inductance at time t = 5.00 X 10'3 s? EA3 7.20X 104V . . _, L: fig} V '7 L 2' 1 35ml“ + it?" 6” (in)
. r g I 31: ' ' . s Y” :c: 6_57x10—4V é{35ml¢s . gut1,5; gla.wd(ttffl’o :02 1.25 x 104V 7 .f7 7 “7"; We I=E=1Noneoftheai>0ﬂ22 5'0 \A ((9 (#0:?) = 90,000 ’ 4 An airplane ﬂying at a distance of 20.9 kmﬂf’rom a radio transmitter receives a signal with a oneizyclgayerage intensity of 4.00 X 10“5 Win12. What is the ampligide (i.e., peak instantaneous value) of the electdeeld intensity at the airplane due to this signal. ( g I <3;>; > ; If}, Farm, v; Eleni" 8—? EA: 0.0549 Wm
erg s 1.00 x 10 Wm’) :03 2.00 X 10' Wm
ED:l 672 Vim
CE: None of the above 5 An image formed by a plane mirror is always
CAD inverted.
L=B 3 on the same side of the 'mirror as the object.
CC: half as far from the mirror as the object is.
ED: twice as tall as the object is. ,1: I _‘ 6/ ; w “4.2;” s» ‘ 
Zf/y paw r  :‘53?3 I
“2% The electric flux in a parallel plate capacitor is changing at a rate of 200 the displacement current
ﬂowing from one plate to the other? K (a _,{ ff; l.  :A: 2.26 x 1013 A on V's? _
4 F m
can 2.51x 10 A 9.55 .v at; Wﬂbw 1/ M13) — ~=i
[res—mm  ‘ 33.1.3. CDaisaxlonA __ .___ ._ .____,__ (:NE E3 None of the abet}; ——._....__________,___r._, Kim both a capacitor and an inductor in an ac circuit, the reacmce of the comment p E‘ _ _( v.34. y g dr \1 ; C I l i I
EA:I is directly proportional to the frequency of the current through the component. . . . ., .1/ . , "’r—_“'v—\ EB; is inversely proportional to the frequency of the current through the component. . . micé: is deﬁnedlﬁ; the amplime the voltage across the component divided by the amplitude of the current '? oug e component. a”
e ‘ , p .1
lID =1 is doubled if you double the amplitude of the vo'hge across the component but keep the frequency constant 1: E :1 is halved if y0u double the amplitude of the eurreIitQHrough the component but keep the frequency constant. 310 ~ 35 : L L, MA 4.00cmtall object is placed 30.0 cm in front of a convex (diverging) mirror. If the absolute value of the l 2%“: 4
radius of Curvature of the mirror is 50.0 cm. what is e hei ht of the image? 4', ) R 4 = "a .{l}. t 1%. =
I EA3 8.800111 (J4) Tqm J— +L ‘ A 33"
EB: r  1MP ,3“; (1 Sr «:0 149. x a.
307:1? ﬁl C: to; 20.0 we
— Z. 1 5 ;? ‘ 5:1'.‘ " A !
r:Ert None ofthe above 5 *’ ~— i P" r 3.3 i =3, Kl: 41:9
’3 So
9 A converging lens has a focal length of absolute value 50.0 cm. An object is placed 30.0 cm in front of the lens.
Where is the image?
’ﬂ—ﬁ"—~mciirﬁ—'"Hﬂ—_Z=h I" ‘\ —‘. ‘f‘ E = mimﬂmﬂthelens’ y: W p < f g 6
:B: 75.0 cm behind the lens I; T T f I L
:03 18.8 cm in front of the lens. ’7 ,4  "i "=0" " ism t 3; + L ‘ LTD
:13: 18.8 cm behind the lens. a—  ' \ /
t — 7900 CE 2' None of the above 10 An ac generator of with a voltage amplitude of 20.0 V is connected to a series circuit containing a 50.00
resistance, a capacitance, and an inductance. At a certain generator frequency, the reactances of the capacitance
and inductance are 80.0 .0. and 120 .0. respectively. What is the amplitude of the current through the circuit at q \ \f . XL 1. 3th
:1 0.312A 1 30“ QOJL 6 X '_ 1:10.11 :13: 0.0800A cc: 0.131 A ' :0: 0.222 A y. , t. 7' 0 ,7 L “GEENone ofthe above m 1., ,rf/ L ﬂ ~<
1—1\C_ 72:7 30 1 ' h is true? ' _
I: Maxwell’s equations consist of four new laws of electromagnetism that are not related to Coulomb’s law.
theBiot—Savart law. or Faraday's law, and must therefore be added to them to form the seven basic laws of electromagnetism.
Chg Magnetic monopoles have been discovered, so there is a Gauss’ law for magnetic ﬁelds that is exactly the
same form as that for electric ﬁelds. '
axwell’s equations can be used to predict the existence of electromagnetic waves as well as to derive their
' propagation speed. , 
'3 '3 Ordinary (ﬂanking charge) current can produce magnetic ﬁelds, but Maxwell‘s displacement current cannot
produce magnetic ﬁelds. '
C Maxwell introduced no new physics in writing his equations; he simply wrote previous laws in a different
farm. 
2 Which is true? .  A _ The focal ipngth of a spherical mirror is twice its radius of curvature. K 
/ r: :n A spherical mirror can never produfce an image that is larger than the object. ____ f .‘__'_ .__;.., .
' The greater the radius of curvature of a spherical mirror, the shorter its focal length. \\
I: A mirror that is ﬂat and not curved cannot produce an image. 7 v 9
"if: E3 e image produced by a diverging (convex) spherical mirror is always virtual.
3 For both a capacitor and an inductor in an ac circuit, the reactance of the component W L I X _ ‘  15 directly proportional to the frequency of the current through the component. we L a 3:. is inverser proportional to the frequency of the current through the component. is deﬁned as the amplitude of the voltage across the component divided by the amplitude of the current
through the component. ‘ ‘  ' C D 3 is doubled if you double the amplitude of the voltage across the component but keep the frequency constant.
I: E I! is halved if you double the amplitude of the current through the component but keep the frequency constant. 4 What is the time constant for charging a 3.00—trF capacitance with a 6.00V battery having an internal resistance of
0.500 .0? . l 7 , k a" ' In .5 x :3: 4.00145 “’i i’" .
:c:_ 9.00m _ . A, 1' t" at
CED None of the above V ‘ 5" behiiid the lens. What is the absolute value of the focal length of the lens?
E A3 70.0 cm
I: B a 30.0' cm
cc: 33.3 cm 5/0 _ .3: o" no 3715 cm  A _A __1t.__..r_.._: {5 None of the above :1 2 O 5 When a candle ﬂame is placed crn'in front of a lens, an image of the ﬂame is projected on a screen 50.0 cm 6 What is the maximum instantaneous energy density in a plane polarized radio wave (the only type we discussed in
traveling in a vacuum if its electric ﬁeld intensity oscillates with an amplitude of 4.00 Vim? z a“
.42x10m 11m3 2 _ W,» zfa“ 24 6.5 f 2.01x105 Jlm3  ' r — “r. c : 1.01x105nm3 ’ a) ‘ @haxw“Jm 2 (1’ got J C E 3 None of the above . 7 An AC circuit contains a resistance. capacitance, and inductance in series. The resistance is 4.00 .0, the reactance
of the capacitance is 6.00 0., and the reactance of the inductance is 8.00 ﬂWhat is the phase difference between
the voltage across and current through the circuit? C A: The current leads the voltage by 26.6' 7 a“; i J __ * VL " Y"
\/ The voltage leads the current by 266° LP— , if...
E CI! The current leads the volta e b 90.0“  
. g. Y . g L]. M E’
E Ill:l The voltage leads the currenth 90.0“ "
cE: None ofthe above ' ’Uolucl , (“n/gafw 8 A laser on the ceiling of a room shines a vertical ray of light d wn onto a mirror lying ﬂat on the ﬂoor. Someone
raises oue edge of the mirror until it is tilted 20.0“ from the or. In what direction does the reﬂected ray now
travel? .4 CA3 10.0” above horizontal
71 .0“ above horizontal
 20.0' above horizontal ‘ C 3 40.0“ above horizontal ‘ _ ~ E 53 None of the above l' .I " "“ I "/>o 9 A certain circuit consists of resistances, capacitances, and inductances. When the sinusoidal ac voltage across it 722
has a root—mean—square value of 5.00 V, the current has a rootmean—square value of 4.00 A. If the phase difference
between the voltage and current is 30.0“, what average power does the circuit dissipate? if E :l ‘1' ' '  ../‘ A 600‘” (fat3— 8h? ' ’20” W m7 a “gt. : a: 69.3 w {git ‘ 2 — s I m '2 ﬁt. “1 a
@173 w 4 ‘— ﬂ‘") ' A i ‘ I t = 3 174’ “at:
t: :I 10.0‘W I S ' '
None of the above  retraction of water is 1.33. What is the critical an e of incidence for total'intemal reﬂection at the plastic~water '1 1555
interface? In which material must the incident light 3* be traveling in order to produce total internal reﬂection? CA3 29.3“,mcidentraymwamr W” N {N i» If) I; I: B =1 29.3“, incident ray in plastic ‘ M g
@ 60.7“, incident ray in water ~_._ 3. ‘9 it,” {JAE} _ £3! <5
2 o 2 50.7“, incident ray in plastic 3 3’0 (VA :55 g
, i r' ‘ w m NV »
. t: E3 None of the above gr 4;“ hr? H
F (xiA ‘Gl‘o I \
/\ ( ‘1 c) k 9 I i Qj 43...
9 _ / f" O I” \j
( t" 3 3;
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This note was uploaded on 03/01/2012 for the course PHYS 202 taught by Professor Johnmeriweather during the Spring '09 term at University of Louisiana at Lafayette.
 Spring '09
 JOHNMERIWEATHER
 Physics

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