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Unformatted text preview: • If you kept track of this as you did this, then you would
have something that looks like this: 1,2
12, 13 14 15,16,17,18
o If you see, I just kept a tally of how many isomers
we had gotten to at each spot.
So here, there are 20 total monochlorinated
products possible. Allenes
o Chiral compounds with no chiral carbons
o Two double bonds directly next to each other
C A C
D B o For the molecule to be chiral, A≠B AND C≠D Fischer Projections
H2 N H CH3 o Every intersection is a chiral carbon. o Everything on the horizontal is coming forward and everything on
the vertical is going back
H2 N H
CH3 If you are asked to convert from Fischer to line-angle
you cannot just draw the dashes and wedges like I’ve
done here. Two of the pieces coming off any atom must
be drawn flat (in the plane). o Still assign priorities the same way as before
2 CO2H H2 N
3 CH3 o Draw your circle from 1 to 2 to 3
2 CO2H H2 N
3 CH3 o If H (or any lowest priority group) is on the Horizontal, it’s Horribly
Wrong! It looked like an R, but H was on the Horizontal so it’s an S. ...
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This note was uploaded on 03/06/2012 for the course CHEM 301 taught by Professor Sahli during the Spring '07 term at VCU.
- Spring '07