Unformatted text preview: We also use α f =1dB/km, α con = 2dB, M s = 6 dB, α splice = 0.2 └ L/2 ┘ dB. Thus, we solve for L and obtain L=20 km. Problem 5.9. From Eq.(5.2.11) and Eq.(5.2.12) in text, we have 2 2 2 mod 2 2 rec GVD la tr r T T T T T + + + = . Now, T tr = 10 ns and T rec = 15 ns. Also for a graded-index fiber, T modal ≈ (n 1 ∆ 2 /8c)L= 0.60 ns. Also, T GVD = |D|L ∆λ = 40 ns. Thus, T r = 43.9 ns. From Eq.(5.2.10), we know that T r should be < 0.35/B = 7 ns for RZ modulation and T r should be < 0.7/B = 14 ns for NRZ modulation. Hence, none of these formats can be supported using the current system....
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- Spring '11
- 0.1 mW, 20 km, 1 mW, 0.2 L, 1-C}n-1.