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Unformatted text preview: We also use f =1dB/km, con = 2dB, M s = 6 dB, splice = 0.2 L/2 dB. Thus, we solve for L and obtain L=20 km. Problem 5.9. From Eq.(5.2.11) and Eq.(5.2.12) in text, we have 2 2 2 mod 2 2 rec GVD la tr r T T T T T + + + = . Now, T tr = 10 ns and T rec = 15 ns. Also for a graded-index fiber, T modal (n 1 2 /8c)L= 0.60 ns. Also, T GVD = |D|L = 40 ns. Thus, T r = 43.9 ns. From Eq.(5.2.10), we know that T r should be < 0.35/B = 7 ns for RZ modulation and T r should be < 0.7/B = 14 ns for NRZ modulation. Hence, none of these formats can be supported using the current system....
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This note was uploaded on 03/06/2012 for the course ENGINEERIN 605 taught by Professor Rahmir during the Spring '11 term at Wisconsin.
- Spring '11