Lec-11-Chap13,15-3,1-Complete

Lec-11-Chap13,15-3,1-Complete -...

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Lec-11-Chap13,15-3,1-Complete 9/28/2011 Directionality of Chemical Reactions Gibbs free energy of reactions in non- standard conditions. Chemical Equilibrium 1 Lec-11: Thermodynamics: Directionality of Chemical Reactions. Gibbs Free Energy Chapter 13 Chemical Equilibrium, Chapter 15 1 Wednesday, September 28, (in the first half of the lecture) Discussion about the course with Professor Troy Wolfskill Professor Fernando Raineri Directionality of Chemical Reactions. Gibbs Free Energy The change in the Gibbs free energy ( G = H – T S ) of the reaction involves only properties of the system. In standard conditions the criterion for spontaneity is spontaneous 0 constant and 1bar G H T S Tp           where 0 , in reactan 0 , in products ts P f P P R f R R H H H     0 in reactants 0 in products PP P RR R S S S 2
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Lec-11-Chap13,15-3,1-Complete 9/28/2011 Directionality of Chemical Reactions Gibbs free energy of reactions in non- standard conditions. Chemical Equilibrium 2 Directionality of Chemical Reactions. Gibbs Free Energy The change in the Gibbs free energy G of the reaction involves only properties of the system. 3 0 , in reactan 0 , in products ts P f P P R f R R G G G      We may calculate ∆Gº from the standard free energies of formation of the substances participating in the reaction: C+ D+ A+ B+ ab cd     0 00 ,, 0 0 fA D B C f ff c G d G a G b G G   For the reaction: Calculate the standard Gibbs free energy of the reaction at 298 K and 1 bar.       2 2 1 CO g O g 2 CO g             2 1 2 01 0 0 CO g O 137.168 kJ mol 0 394.359 kJ mo g CO g l f f f G G G  4
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Lec-11-Chap13,15-3,1-Complete 9/28/2011 Directionality of Chemical Reactions Gibbs free energy of reactions in non- standard conditions. Chemical Equilibrium 3 Directionality of Chemical Reactions. Gibbs Free Energy       2 2 1 CO g O g 2 CO g     0 in reactan 0 in products ts Pf P Rf R G G GP R                      0 0 0 2 1 2 0 1 1 CO g 394.3 2 1 CO g O g 2 137.168k 59kJ 57.1 mol 91kJ m J mo ol l f f f G G G G G G      5 Calculate the standard Gibbs free energy of the reaction at 298 K and 1 bar.         2 F F eO es s CO g g + CO              0 1 2 01 1 0 255.2 kJ mol 137 Fe .3 kJ mol 394.4 kJ Os C mo Og l C f f f G G G  Answer: (1) (1): -1.9 kJ/mol (2): -276.5 kJ/mol (3): 512.3 kJ/mol (4): -257.1 kJ/mol (5): More info required 6
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Lec-11-Chap13,15-3,1-Complete 9/28/2011 Directionality of Chemical Reactions Gibbs free energy of reactions in non- standard conditions. Chemical Equilibrium 4
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This note was uploaded on 03/06/2012 for the course CHE 132 taught by Professor Hanson during the Fall '08 term at SUNY Stony Brook.

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Lec-11-Chap13,15-3,1-Complete -...

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