Lec-13-Chap15-3-bare

Lec-13-Chap15-3-bare - Lec-13-Chap15-3-bare 10/2/2011...

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Lec-13-Chap15-3-bare 10/2/2011 Chemical Equilibrium Concepts. Equilibrium constant. Uses 1 Lec-13: Chemical Equilibrium Chapter 15 1 C+ D+ A+ B+ ab cd For a reaction         D AB C c K the equilibrium constant expression is Notice that the concentrations correspond to the equilibrium state , for example [A] e . For simplicity we omit the subscript “e” in the following. Equilibrium Constants: “multiplying” reaction equations            22 1 2 2 2 HO H O g 1 H g O g 2 + c K The numerical value of the two equilibrium constants is very different .              21 2 2 2 2 2 2 H O H H O O cc KK    please don’t!!!!!!!!!!!! 2             2 2 2 2 2 2 2H O g 2H g O g + c K For example multiply the chemical equation by 2:
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Lec-13-Chap15-3-bare 10/2/2011 Chemical Equilibrium Concepts. Equilibrium constant. Uses 2 Equilibrium Constants: Combined Reactions                        1 2 2 2 2 2 22 2 2 2 N g O g NO 2NO NO 2NO g NO 2 NO g g O g + NO O c c K K             2 2 2 2 2NO g N g 2O g c K                 2 2 2 2 2 2 2 1 N NO NO O O c c c K K K  3 4 Chemical Equilibrium – Gas phase reactions For reactions in the gas phase we can use         D AB C cd ab c K or an equilibrium constant formulated in terms of the partial pressures of the gas species present in the mixture at equilibrium: C D p P K P P P
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Lec-13-Chap15-3-bare 10/2/2011 Chemical Equilibrium Concepts. Equilibrium constant. Uses 3 Chemical Equilibrium – Gas phase reactions Ideal gases satisfy the equation of state P V T n R If we have a mixture     AB A B Vn P P P P n n P T n R n A A P V T n R which gives the following expression for the partial pressure of a substance in the mixture: And similar equations for the other substances B, C, … 5 Chemical Equilibrium – Gas phase reactions We can then write for the partial pressure of each substance   A A A R n V P T RT      D A C B ab d cd c c RT PP R K T   we can express the right-hand side of the equilibrium constant equation as C+ D+ A+ B+ Then for the chemical equilibrium         D C c K 6 And similar equations for the other substances B, C, …   A A T
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This note was uploaded on 03/06/2012 for the course CHE 132 taught by Professor Hanson during the Fall '08 term at SUNY Stony Brook.

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Lec-13-Chap15-3-bare - Lec-13-Chap15-3-bare 10/2/2011...

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