hw07_rocket_ssukhwal - time(sec)= 1 20000 21 1460 2400 50...

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ENGR 13200 - Spring 2012: Name(s) : Siddharth Sukhwal Purdue Email Address(es): Section #: 10 Assignment #: Homework 7 Problem 3 I/We have not used material obtained from any other unauthorized source, either modified or unmodified. Neither have I/we provided access to my/our work to another. The solution I/we am/are submitting is my/our own original work. Problem Description: Input Section: Output Section: g(m/sec^2)= 9.81 Case No. h_desired(m) q(kg/s) me(kg) u(m/s) b(sec) Time to reach h_desired (sec)
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Unformatted text preview: time(sec)= 1 20000 21 1460 2400 50 53.4 current_height(ft)= 2 20000 10 850 1800 30 Rocket can't achieve the desired height time_initial(sec)= 0.1 3 22000 26 3400 3250 60 68.7 Calculations: Case 1: m0= 2510 v(b)= 74.2700776718 h(b)= 839686.752932175 hp= 839967.896889228 Case 2: m0= 1150 v(b)=-57.9979536492 h(b)= 718390.259081019 hp= 718561.704678751 Case 3: m0= 4960 v(b)=-55.5910317942 h(b)= 107640.827234625 hp= 107798.338081513 ssukhwal@purdue.edu...
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This note was uploaded on 03/06/2012 for the course ENGR 132 taught by Professor Kutson during the Spring '11 term at Purdue University-West Lafayette.

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