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2010 Exam 2 - NAME_KEY MIDTERM EXAM II BIOLOGY 231 18...

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NAME: ________KEY_________________ MIDTERM EXAM II BIOLOGY 231 18 October 2010 ________________________________________________________________________________ READ THESE GENERAL INSTRUCTIONS: 1. Answer all questions IN INK. 2. NO CALCULATORS. 3. Confine each answer to the BOX or SPACE provided. You are free to use the blank pages for scratch work, but ONLY what is written in the box or space will be graded! 4. Show your work in all calculations. Render numerical answers in decimals and check your units. 5. Make sure that your name is PRINTED LEGIBLY on EACH PAGE. 6. This exam consists of 8 questions on 13 pages (plus one blank page for scratch work) and it is worth a total of 100 points. Here’s some information that may be useful: ! 1M = 10 mM = 10 μ M; 1V = 10 mV 3 6 3 ! log(10 ) = X; log(10 /10 ) = log(10 ); 10 /10 = 10 X X Y X Y X Y X Y ! for a transmembrane gradient of any solute X, the free energy of the gradient is found by: X in out m G = RT ln([X] /[X] ) + zFV in out m = 5.7 kJ/mol log([X] /[X] ) + zFV “in” = cytoplasmic; “out” = extracellular or non-cytoplasmic space; z = valence of the ion; F = Faraday constant = 10 kJ/V mole 2 X out in ! at equilibrium, the Nernst equation gives us: V = (59mV/z) log([X] /[X] ) X m X ! for a charged molecule X: G = zF(V V ) ! for a proton gradient: G = F( p) ! the protonmotive force, p = ψ (59mV pH) m IMS matrix where ψ = V of IMM; pH = (pH pH ); IMS is the intermembrane space ! when a negative number increases, it becomes more positive m ! when a positively charged ion leaves the cytoplasm, the V becomes more negative ! On this day, October 18 1867, the US took possession of Alaska, which it had purchased from th, Russia for 2 cents an acre. -1-
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NAME: ________KEY_________________ MIDTERM EXAM II BIOLOGY 231 18 October 2010 ________________________________________________________________________________ THE GENETIC CODE (Single letter abbreviations for amino acids) 2nd U C A G 1st 3rd U F S Y C U F S Y C C L S term. term. A L S term. W G C L P H R U L P H R C L P Q R A L P Q R G A I T N S U I T N S C I T K R A M (init.) T K R G G V A D G U V A D G C V A E G A V A E G G -2-
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NAME: ________KEY_________________ MIDTERM EXAM II BIOLOGY 231 18 October 2010 ________________________________________________________________________________ (1) 20 pts. The diagram below depicts three organelles in a plant cell: the ER, a mitochondrion (M), and a chloroplast (C) . It shows 12 different sites or paths of movement in the cell, numbered 1 - 12. These are: (1) = anywhere in thylakoid lumen; (2) = within thylakoid membrane; (3) = anywhere in stroma; (4) = movement from stroma across thylakoid membrane into lumen; (5) = opposite direction to (4); (6) = anywhere in matrix; (7) = within IMM; (8) = mitochondrial IMS; (9) = movement from matrix across IMM to IMS; (10) = opposite direction to (9); (11) = cytoplasm; (12) = lumen of the ER; 13 = OMM. In each box below, write the number(s) of the correct location(s) where the item takes place. Note that either one or two answers may apply to each; choose ONLY the appropriate answer(s) for each. FUNCTION LOCATION 2 CO + ATP + NADPH => carbohydrate 3 H flow in this direction through ATP synthase + 5,10 glucose => => => pyruvate 11 ATP accumulates due to action of ATP synthase 3,6 chlorophyll captures photons 2 ions cross freely between compartments via porins 13 electron transport chain undergoes redox reactions 2,7 2 2 ½ O + 2 H + 2e => H O + 6 (or 7) 2 isocitrate => alpha-ketoglutarate + CO 6 NAD + H => NADH + : 6,11 ionic composition very similar to cytosol 8
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