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Unformatted text preview: t and write your FINAL ANSWER in the box at RIGHT. Be careful with UNITS. Na+ W ork ￿ G Na (k J /m o l) Ä G Na = zF (V m ￿ V Na) ￿ 12.9 kJ/m ol ÄGN a= (1)(102 kJ/V mol)(1 V/103 mV)(￿70 mV￿59 mV) = (0.1 kJ/mV mol)(￿129 mV) = ￿12.9 kJ/mol K+ W ork ￿ G K (k J /m o l) Ä G K = zF (V m ￿ V K ) ￿ 1.1 kJ/m ol ÄGK = (1)(0.1 kJ/mV mol)(￿70 mV￿(￿59 mV)) = (0.1kJ/mV mol)(￿11 mV) = ￿1.1 kJ/mol 4( c) 3 pts. Suppose that you wanted to drive K+ uptake in the axonal membrane of these neurons using the energy of the Na gradient via a Na/K antiporter. What would be the MAXIMUM ratio of molecules K+ : molecules Na+ in each cycle of this antiporter that would work, energetically? (Answer should be an INTEGER) 1 1 K + to 1 N a + [11 × 1 .1 kJ/m ol = 1 2 .1 kJ, just u nder 12.9 kJ. N ote: this w ould m ean 94 % efficien cy for the transp orter!] -7- NAME: __________KEY________________ MIDTERM EXAM II BIOLOGY 231 19 October 2009 ________________________________________________________________________________ (5) W e sa w in lec tu re th a t th e e lec trica l p ro p e rties o f n e u ro n a l m e m b ra n e s a re m a in ly d u e to properties o f s pecific integral m...
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This note was uploaded on 03/12/2012 for the course BIO 231 taught by Professor Hollenbeck during the Fall '11 term at Purdue University-West Lafayette.

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