2009 Exam 2 key

2009 Exam 2 key - Exam 2-2009, p. 1 Biology 131,...

Info iconThis preview shows pages 1–12. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Exam 2-2009, p. 1 Biology 131, Examination 2-, Spring, 2009 K E j/ Name (PRINTED IN CAPITAL LETTERS) \ ~ '7 Purdue Email: Waive . 65» ‘4 What did you do to prepare for this exam? Please share their thoughts by answering these questions. It may take you 5 minute to answer these questions. COMPLETION OF THIS FORM IS ENTIRELY OPTIONAL! If you decide to do this, we will not look at our answers until after the rades are osted. If you check yes, then place an “X” in a box to the right extremely useful DID YOU DO THIS? Re-read the textbook No: Yes’: ifso wasit Review my own notes from N0 Yes ifso was it lectures ’ ’ Review lecture powerpoints NO Yes D ifso was it , ’ Hear recordings of lectures No D Yes I: ifso was it i , Read lecture notes taken by NO 9: Yes if so was it someone else a , Read the exam handout N0 Yes ifso was it 9 a y Work the problem set N0 Yes ifso was it ‘ Review Blackboard quizzes No 2' yes ifso was it Practice with CPR essays N0 Yes ifso was it Work old exam problems No '3 Yes ifso was it Attend help sessions N0 yes C’ ifso was it . . r‘] F" . . ViSit the BRC No .___ Yes _, if so, was it Discuss in a study group No yes C" ifso, was it r“ A- Studvalone Use the BIOL13100 WIKI N0 yes ifso was it Get enough S'eeP No Yes if so, was it ‘b v IIHIIIEIIEI-II-Im “enliven-um g v \ y -’ / neutral III-IIII-IIIII-I- ' / / A ~ s ' ' \ ‘ '9 C‘ Exam 2-2009, p. 2 Biology 131. Examination 2, Spring, 2009 V E U / I Name (PRINTED IN BLOCK LETTERS) ~ ‘ Signature ~' ; . * r. . . JPUID; . . . Genes/u. INSTRUCTIONS: o This exam consists of 135 questions on 20 pages. It is worth 200 points. 0 NO CALCULATORS OR ELECTRONIC DEVICES! Turn off and stow cell phones. 0 Please keep your answers covered as you work and KEEP YOUR EYES ON YOUR OWN PAPER AT ALL TIMES! 0 Do not leave the room until you finish this exam. MULTIPLE CHOICE QUESTION INSTRUCTIONS: I. Choose the one alternative that best completes the statement or answers the question. N. Mark the answer carefully on your answer sheet. Bubble your answer sheet completely in PENCIL and erase stray marks. Multiple answers are marked wrong. Ill. You MUST write and bubble in both your name and PUID on the answer sheet and on EVERY PAGE of this exam where indicated, because the exams may be disassembled for grading. (40 items x 2.5 pts each = 100 points) 1] Put the following events in the process of signal-transduction in order: 1. A conformational change in the signal-receptor complex activates an enzyme. 2. Protein kinases are activated. 3. A signal molecule binds to a receptor. 4. Target proteins are phosphorylated. ' 5. Second messenger molecules are released. ) l I A G-protein receptor with GTP bound to it __ @is in its active ‘state. B] autophosphorylates its tyrosine residues. C) will use cGMP 3521 second messenger. D) directly affects gene expression. E) all of these are true. 3) Gastrulation is an important event in early embryonic development. Which of the following is not a result ofthis process? A) formation of threetembryonic cell layers B) movement and alignment ofmany embryonic cells C] determination ofcell types as a result of cell—cell interactions formation of specialized plant tissues E) all of these are a result ofthis process Exam 2-2009. p. 3 4) Communication within and between cells ofan embryo can include all ofthe following except . A) increased concentration of signaling molecules. B) changes in binding to regulatory sequences. 6% changes in gene transcription. changes in gene sequences. E) changes that cause apoptosis. 5) What happens during gastrulation? A) The neural tube—precursor of the spinal cord and brain—forms. B) Basal and apical cells—precursors ofthe suspensor and embryo, respectively—form. _ The fertilized egg divides without growth occurring, forming a ball of cells. Massive movements of cells make the primary body axes visible and organize the three embryonic tissues. 8) All of these happen during gastrulation 6) One unique feature of fertilization in flowering plants compared with animals is that _. A) plant sperm are motile. B multiple ovules exist in the ovary. the process involves double fertilization. D) nuclear fusion does not take place. E) the gametes are diploid, not haploid. 7) All ofthe following statements are true of the endosperm except that A) it may be likened to the yolk ofan animal egg. B) it is a triploid tissue. fin is used as a food source by the embryo. it is formed from equal contributions of both parents. E) it is the major energy source for germination. 8) What is true about plant meristematic cells? A) They are distributed evenly in all tissues throughout the plant. They are undifferentiated cells that produce new cells. ) They produce outgrowths called root hairs. D) They subdivided into three distinct cell types named parenchyma, collenchyma, or sclerenchyma. E) They are the main cells involved with transpiration. 9) he main source of water necessary for photosynthesis to occur in the leafmesophyll is soil via the xylem. soil via the phloem. C) the atmosphere through the cuticle and stomata. D) water produced by metabolic reactions in the cell. B) all of the above. Exam 2-2009. p. 4 10) Water potential (:31) can be thought of as the tendency for water to move from one place to another. in plants, it is made up mainly of solute potential and hydrostatic potential (pressure ). Hypothetical plant cells A and B are adjacent to each other. The solute potential (ll) 5) of cell A is -0.35 MPa, and its pressure potential (dip) is +0.15 MPa. The solute potential (1]! s] ofcell B is -0.30 MPa, and its pressure potential (dip) is +0.05 MPa. in which direction will net water movement occur? A) Neither; cells A and B are in equilibrium with each other. 9r om cell A to cell B from cell B to cell A D] There is no way to answer because it depends upon their membrane potentials. E) There is no one correct answer because it depends upon the pH inside each cell. 11) As an undergraduate research assistant in the lab of Dr. Osmo, your duties involve measuring water potential in experimental soil-plant-atmosphere systems. Assume you make a series of measurements in a system under normal daylight conditions, with stomata open and photosynthesis occurring. Which of the following correctly depicts the trend your measurement data should follow if the cohesion-tension mechanism is operating? A] ll] soil < q: roots = II} leaves < \IJ atmosphere B] LI: atmosphere < q; leaves = iii roots < q; soil C q; soil < ll! roots < q: leaves < ll! atmosphere @ atmosphere < ll: leaves < 111 roots < [D soil All of these trends are possible when the cohesion-tension mechanism is operating. 12] To find the gene that encodes for the blue-light receptor, researchers inserted the gene for the PHOTI protein into insect cells growing in culture. When they exposed the transgenic cells to blue light, they found that the PHOT1 protein became phosphorylated. No other plant proteins were present in the insect cells. Which of the following is a reasonable conclusion from this result? A) The PHOT1 protein enabled the insect cells to photosynthesize. The PHOTl protein phOSphorylated itself in the presence of blue light. ) The PHOTI protein is not responsive to blue light. D) The PHOTI protein is photoreversible. E) The PHOT1 protein is not functional in insect cells. 13] The turgor pressure of a cell is the difference in hydrostatic pressure between the inside and outside of the cell when water is at equilibrium. If the total solute concentration inside a cell is 300 mM and the total solute concentration outside the cell is 100 mM, what is the turgor pressure of the cell? Assume the equilibrium condition for water. Remember, 1L = 10‘3/m3 and that 1 Pa = 1 joule/m3. A) 2.4 atm B] 0.24 MPa 240,000 Pa Q 0.48 MPa 0.48 atm Exam 22009, p. 5 14) What is the chemical nature of the specialization of plant cells that allows them to have turgor pressure? A) protein B] lipid C glucose D carbohydrate polymer )add 15] To understand how plant phototropic responses are regulated, a researcher performed the following experiment. He exposed oat seedlings to light and then cut off tips of coleoptiles and placed them on agar blocks. Later the agar blocks were placed on decapitated coleoptiles of other individuals. and some seedlings were kept in dark while others were exposed to light. Based on your knowledge of auxin synthesis and mode of action, predict in what cases the decapitated coleoptiles would bend to the left. A) when the block was placed on the left side ofthe coleoptiles in both dark and light atments - hen the block was placed on the right side of the coleoptiles in both dark and light treatments C) when the block was placed on the left side of the coleoptiles in dark only D) when the block was placed on the right side of the coleoptiles in dark only E] as long as light was coming from the left, decapitated coleoptiles bent to the left independently of agar block placement 16] Suppose a plant had a photosynthetic pigment that absorbed far-red wavelengths of light. In which of the following environments could that plant thrive? on the floor of a lake, whose water contains abundant green algae B) n the forest floor, beneath a canopy of taller plants C) on the ocean floor, in very deep waters D) on mountaintops, closer to the Sun E] None of these; plant pigments absorb blue light instead of far-red wavelengths. 17) in concentration of auxin in shoot cells and in concentration of auxin in root cells lead to cell elongation. A) Increase; increase @lncrease; decrease C) Decrease; increase D] Decrease; decrease 18) Flowering plants are unique in having double fertilization that forms endosperm. What is true about double fertilization in angiosperms? A] Two sperm combine with a polar nucleus to form endosperm. B) Two sperm combine with two eggs to form the zygote and endosperm. C) One sperm combines with the polar nuclei to form the zygote, and one sperm combines with the egg to form endosperm. One sperm combines with the egg to form the zygote, and one sperm combines with the polar nuclei to form endosperm. Exam 2-2009, p. 5 opposite surface. What property of these cells allows them to have these various functions? A) Epithelial cells are polar. B] Epithelial cells have an apical membrane and a basolateral membrane. C) Epithelial cells have different proteins in different parts oftheir cell membrane. . Only A and B are true. , B, and C are all true. 20) Which of the following is not considered a second messenger? A] CAMP B l P3 orepinephrine D] DAG E) all of these are considered second messengers (. 21) Receptors on the surface of the target cell A) may allow a particular ligand to bind. B] determine the target cell's response. C bind to all ligands. A and B E] B and C B] Cl" C) K' D) Na* E) none of the above a 23] lnositol triphosphate A] is a hydrophobic messenger molecule. B) binds to the calcium channel ofthe endoplasmic recticulum. 5m involved in the release ofcalcium into the cytosol. D B and C E) all of the above 24] When norepinephrine (NE) bind to receptors, A] it opens Ca2*channels in the membrane, or releases Cab both. from storage inside the cell, or B) it causes some vascular smooth muscles to contract. C) a second meSSenger cascade is initiated. D) it causes an increase in phosphorylase activi stores. @All of these statements are true. ty which liberates glucose from glycogen 25] Nicotinic receptors A] are integral membrane proteins. 13] bind ACh and open cation channels. L] are kinases that ca :1 atitophmphorylate. *‘ D]]Aand B KETA, B, and (I 26] When aclenyl cyclasc is activated, AMP is formed. calcium ions are released from intracellular stores. C] protein kinaSes are metabolized. D] cAMP is broken clown. ' E] guard cells are depolarized. # 27] When calcium becomes available inside a cell, it comes from A] intracellular storage. B] extracellular fluid. fC]\it is always available as a major cytoso] catiOn. .r D] A and B "'E] None of these are true. __,28] One intracellularcalciuin—binding protein is 'lficalmodulin. 1)) “’3 1-1) DAG 29] What is the first event in the opening ofa stoma in a leaf? A] Water influx into the guard cell. [3] Water efflux from the guard cell. C] Membrane depolarization (Vm becomes more positive]. Activation ofblue light receptor. E] Activation ofreceptor by ABA. 31.0] What is the last event in the opening ofa stoma in a leaf? [A] Water influx into the guard cell. 8] Water efliux from the guard cell. C] Membrane depolarization (Vm becomes more positive]. D] Activation ofblue light receptor. E] Activation ofreceptor by ABA. Exam 2-2009. p. 7 " Exam 2-2009, p. 3 31) What is the first event in the hormone-induced closing ofa stoma in a leaf? A) Water influx into the guard cell. B) Water efflux from the guard cell. C) Membrane depolarization (Vm becomes more positive). D) Activation of blue light receptor. @ Activation of receptor by ABA. 32) What is the last event in the hormone-induced closing of a stoma in a leaf? A) Water influx into the guard cell. Water efflux from the guard cell. C) Membrane depolarization [Vm becomes more positive). D) Activation of blue light receptor. E) Activation of receptor by ABA. 33) Below is the absorbance spectra for the two forms of the phytochrome molecule. The graph shows the fraction of the light that is absorbed (y-axis) by a suspension of the molecules as a function of the wavelength of the light (x axis). L0 Suppose that lettuce seeds that have been stored in the dark are exposed to a pulse of light of wavelength 660 nm. What {— PR form will phytochrome be in and will the seeds germinate? 0‘5 A) PR and no PFR B) PR and yes 6_ C) pFR and no (9 PpRand yes 500 550 600 650 700 750 800 34) How much pressure is required to lift water to the top of a tree that is 50 m tall? A) 10 atm moamm 35) 1f capillarity is to supply the pressure needed from question 34, what must be e radius of curvature at the air-water interface at the end of the 50 m column? #280 nm : 140 nm C) 84 nm D)28nm E) 14 nm Exam 2-2009, p. 9 36) Consider the overall effect of gibberellin (GA) on the seed when GA encounters the cells of the aleurone cell layer. For the response to GA, give the sequence for changes in the following: 1. amylase synthesis 2. cytoplasmic calcium ion concentration 3. production of GA-MYB transcription factors 4. a rise in cytoplasmic cGMP S. amylase secretion A) 4-3-2-1-5 B] 1-2-3-4-5 . C) 2-1-5-3-4 ‘_ Q . h ¥ , , 2-4-3-1-5 -5-4-3-1 The following questions refer to this picture: 37) What cell type is shown? A) blood cell B) aleurone cell root hair cell 8%}perm cell Ej ovule 3 What does structure 1 represent? lcium channels B the lP3 receptor C) the ryanodine receptor D) a plasma membrane calcium ATPase pump E) a hormone receptor 39) What does structure 2 represent? A) calcium channels B) the IP3 receptor \the ryanodine receptor (1%} plasma membrane calcium ATPase pump E) a hormone receptor 40) What will be the fate of the membrane at the top of this diagram, if this cell gets lucky? A) It will secrete glucose from carbohydrate digestion. B) It will cause water influx into the acrosomal vesicle. 1% \It will secrete new material to produce new cell wall. (1%,lt will fuse with the plasma membrane of another cell. E) All of these. Exam 2-2009, p. 10 Name (PRINTED IN CAPITAL LETTERS) K E \l 41] BUBBLE IN LETTER A on your answer sheet. Then answer A to I below. Signaling by norepinephrine [NE] through the receptor shown below finally results in the activation ofProtein Kinase A [FHA] and modification ofa particular class of calcium channels. Shown in the figure to the Ieftra re some events in this process. Identify the components A-H. You may find that the same component is identified more than once. Use usual abbreviations, ifyou wish, except for E. [4 pts each] 1 l Extracellular sldl Plasma membran- Cyioplasrmc sud: ' l A J« cr K. ficcp‘o‘nr l G — i B ‘5 @r‘oTF’r-n SRth/(MI: 1} l c 69b? G 0A M? H 7? LJ l lfthe following is an amino acid sequence from a region ofthe calcium channel that is modified by this signaling pathway, indicate the effect ofNE by showing the appropriately modified R group[s) on the appropriate amino acid[s). l. N-glu—arg-val-glu-ser~|ys-lys~pro-C 1. Ci,l'l1. ,9 , oevmo Exam 2~2009, p. 11 KEY 42. BUBBLE-i-N LETTER A on your answer sheet. Then answer a to h below about an inVestigation published by Shinichir'o lnoue, To'shinori Kinoshita, Masaki Matsumoto,1<eiichi I. Nakayama, Michio Doi, and Ken-ichiro Shimazaki, PNAS 105 [14): 5626-5631, 2008. - Nairiie (PRINTED 1N CAPITAL' LETTERSJ‘ "' ABSTRACT: Phototropins like phototropinl (photl) regulate various blue light responses, including phototropism, chloroplast movements, and stomatal opening. However, the physiological mechanisms remain unknown. This study identified autophosphorylation of Ser-851 in photl from the plant, Arabidopsis. The investigators made transgenic plants with this Ser residue substituted for Ala in photl. The photl-mediated responses of stomatal opening and phototropism were examined after the transformation of the phot1 mutant. In the wildtype, Ser-851 was autophosphorylated rapidly by blue light and dephosphorylation occurred gradually upon darkness. Blue light-specific stomatal opening was measured in transgenic plants expressing mutant photl proteins with the single amino acid substitution of serine 851 for alanine. Measurements were done at 24°C. and results were similar on several different days. Blue light activates the plasma membrane Ht-ATPase via photl by inducing proton pumping in guard cells, and this initiates stomatal opening. The little pumping in the mutant resulted in the loss of blue light-specific stomatal opening. The investigators also measured blue light-induced hypocotyl bending. Hypocotyl bending was abolished in the mutant but the wildtype plants showed almost complete (90 degrees) bending. The authors conclude that autophosphorylation of Ser—851 is a primary step that mediates signaling between photochemical reactions and physiological events. (5 pts each] a. CIRCLE ONE: anecdotal, observational, or W b. Does this study include a categorical variable? Explain. c. Does this investigation establish a cause-and-effect relationship between a treatment and a response variable? Justify your answer: Exam 2-2009, p. 12 Name [PRINTED IN CAPITAL LETTERS) 4 €¢r'%§/’>AI W\ L12 Q. . MMK‘MHD" b x d. Identify ONE treatment Variable: e. Identify ONE response variable: 0‘3“) )c) C ’K 6‘ 9. Label the x and y axes to show wha't'they represent ' the mutant phot1 investigation. 93 $5“, 315+ ..+S§ III-IIIIIIIIIII m --------------I t --------------I m --------------I m --------------I u --------------I m III-IIIIIIIIIIIV” w --------.n m --------.m m --------------I w t III-l... --------------I At m III-IIIIIIIIIIIIIIIIIIII at“ t 0 m -----------------------I ” ------------------------t. w -----------------------I m -----------------------I a ------------------------A“ m -----------------------I P m ------------------------+\ m Inn-IIIIIIII-IIIIIIIIIII r g m w. m. w m h m .m S CI. h. Explainlwhat the bare or data points represent. ...
View Full Document

Page1 / 12

2009 Exam 2 key - Exam 2-2009, p. 1 Biology 131,...

This preview shows document pages 1 - 12. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online