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Unformatted text preview: 14. v = e x yz (xi + y 2 j + zk). The field lines satisfy dx dy dz = 2 = , x y z so they are given by z = C 1 x, ln |x| = ln |C 2 | - (1/y) (or, equivalently, x = C 2 e-1/y ). ...
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- Spring '12