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Unformatted text preview: rate 2 π per unit length along the line. Thus, the integral of a 3-dimensional source gives twice the volume rate of a 2-dimensional source, per unit length along the line. The potential of a point source m dt at ( , , t ) is φ( x , y , z ) = -m p x 2 + y 2 + ( x-t ) 2 . This potential cannot be integrated to give the potential for a line source along the z-axis because the integral-m Z ∞-∞ dt p x 2 + y 2 + ( z-t ) 2 does not converge, in the usual sense in which convergence of improper integrals was defined....
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- Spring '12