15_3_3 - = 3 ± t + t 2 2 + 2 t 3 3 + t 4 2 ²³ ³ ³ ³ 1...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
3. Wire: r = 3 t i + 3 t 2 j + 2 t 3 k , ( 0 t 1 ) v = 3 i + 6 t j + 6 t 2 k v = 3 p 1 + 4 t 2 + 4 t 4 = 3 ( 1 + 2 t 2 ). If the wire has density δ( t ) = 1 + t g/unit length, then its mass is m = 3 Z 1 0 ( 1 + 2 t 2 )( 1 + t ) dt
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = 3 ± t + t 2 2 + 2 t 3 3 + t 4 2 ²³ ³ ³ ³ 1 = 8 g ....
View Full Document

This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.

Ask a homework question - tutors are online