15_3_7 - ds = √ 14 dt and Z x 2 ds = √ 14 Z 1 9 t 2 dt...

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7. The line of intersection of the planes x - y + z = 0 and x + y + 2 z = 0 from ( 0 , 0 , 0 ) to ( 3 , 1 , - 2 ) can be parametrized r = 3 t i + t j - 2 t k , ( 0 t 1 ). Thus
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Unformatted text preview: ds = √ 14 dt and Z x 2 ds = √ 14 Z 1 9 t 2 dt = 3 √ 14 ....
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This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.

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