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Unformatted text preview: 8. is made up of four segments as shown in the figure. On 1 , y = 0, dy = 0, and x goes from 0 to 1. On 2 , x = 1, d x = 0, and y goes from 0 to 1. On 3 , y = 1, dy = 0, and x goes from 1 to 0. On 4 , x = 0, d x = 0, and y goes from 1 to 0. Thus x 2 y 2 d x + x 3 y dy = 0 Finally, therefore, x 2 y 2 d x + x 3 y dy = 0 + 4 1 Fig. 48 1 1 x 2 y 2 d x + x 3 y dy =
2 y dy =
0 0 1 2 1 3 x 2 y 2 d x + x 3 y dy =
3 x2 dx = 
1 x 2 y 2 d x + x 3 y dy = 0.
4 1 1 1  +0= . 2 3 6 y
3 (1,1) 2 x ...
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This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.
 Spring '12
 OnurFen

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