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Unformatted text preview: inside the cone, then the area element on is dS = s 1 + ± ∂ z ∂ y ² 2 dx dy = √ 2 dx dy . Thus ZZ y dS = √ 2 ZZ E y dx dy = √ 2 A y = 2 π....
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This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.
 Spring '12
 OnurFen
 Cone

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