15_5_16 - Z 5 dx Z 2 k p 2 xy x + y √ 2 xy dy = k Z 5 dx...

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16. The surface z = 2 xy has area element dS = r 1 + y 2 x + x 2 y dx dy = s 2 xy + y 2 + x 2 2 xy dx dy = | x + y | 2 xy dx dy . If its density is kz , the mass of the specified part of the surface is m =
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Unformatted text preview: Z 5 dx Z 2 k p 2 xy x + y √ 2 xy dy = k Z 5 dx Z 2 ( x + y ) dy = k Z 5 ( 2 x + 2 ) dx = 35 k units ....
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This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.

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