3.F=xi+yj+zk.The box has six faces.F•ˆN=0 on the three facesx=0,y=0, andz=0. On the facex=a, we haveˆN=i, soF•ˆN=a. Thus the flux ofFout of that face isa×(area of the face)=abc.By symmetry, the flux of
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