This preview shows page 1. Sign up to view the full content.
Unformatted text preview: 11. : r = u cos vi + u sin vj + uk, (0 u 2, 0 v ), has upward surface element r r ^ N dS = du dv u v = (-u cos vi - u sin vj + uk) du dv. The flux of F = xi + yj + z 2 k upward through ^ F N dS is 2 =
0 2 du
0 (-u 2 cos2 v - u 2 sin2 v + u 3 ) dv =
0 (u 3 - u 2 ) du
0 dv = 4 . 3 ...
View Full Document
This note was uploaded on 03/08/2012 for the course MATH 120 taught by Professor Onurfen during the Spring '12 term at Middle East Technical University.
- Spring '12