{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

15_R_7 - 7 r = a sin ti a cos tj btk(0 t 6 r(0 = aj r(6 =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
7. r = a sin t i + a cos t j + bt k , ( 0 t 6 π) r ( 0 ) = a j , r ( 6 π) = a j + 6 π b k . a) The force F = - mg k = - ( mgz ) is conservative, so the work done by F as the bead moves from r ( 6 π) to r ( 0 ) is W = Z t = 0 t = 6 π F d r = - mgz z = 0 z = 6 π b = 6 π mgb . b) v = a cos t i - a sin t j + b k , | v | = a 2 + b 2 . A force of constant magnitude R opposing the motion of the bead is in the direction of
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}