stat100_midterm_2012_solutions

# stat100_midterm_2012_solutions - Statistics 100 Midterm...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Statistics 100 Midterm Spring 2012 7 March 2012 Solutions 1. Short answer questions . (a) IQR = 106- 96 = 10 ; (1 . 5)( IQR ) = 15 , so the lower outlier boundary is 96- 15 = 81 . 82 is inside the boundary and is not an outlier. (b) Using the tables of the standard Normal distribution, the lower 25% of a standard Normal is between- . 67 and- . 68 . It is ok to use either one of these values in the solution. Using- . 67 the value on the distribution of interests will be x = μ + σz = 3- (0 . 5)(0 . 67) = 2 . 67 . The lower 25% of the distribution of interest rates is 2 . 67% . (c) False. In a left skewed distribution, the mean will be pulled down by the small values and will typically be smaller than the median. (d) You can use the standard Normal variable Z for this, since the probability of being 2 . 5 standard deviations below the mean is the same for all Normal distributions. Using the tables of the standard Normal, Pr( Z <- 2 . 5) = 0 . 0062 ....
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

stat100_midterm_2012_solutions - Statistics 100 Midterm...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online