CR1 - CHAPTER 1, REVIEW EXERCISES, page 47 1. Adding x to...

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CHAPTER 1, REVIEW EXERCISES, page 47 1. Adding x to both sides yields 3 3 9 + x or 36 x ≥ − , and x ≥ − 2. We conclude that the solution set is [-2, ). 2. −≤ +≤ ⇒−≤ ⇒ − ≤ 23 17 33 6 1 2 x x x , and the solution set is [-1,2]. 3. The inequalities imply x > 5 or x < − 4 . So the solution set is (,) ( 5 , ) −∞ − 4 . 4. and 2 50 25 5 22 xxx >⇒>⇒> x < − 5 and the solution set is ( −∞ − ,)( 5 ,) 5 . 5. −+ +− = +− = + = 57 2 2 2 22 4 . 6. 51 2 43 2 7 7 7 7 7 1 −− = = == . 7. 26 6 π = −− = 8. 34 423 4 3 423 833 −+− = − + − =− () ( ) . 9. 9 4 9 4 27 8 32 F H G I K J / / / . 1 0 . 5 5 55 2 6 4 64 2 = . 5 11. (3 4) -2 = 12 -2 = 1 12 1 144 2 = 12. (-8) 5/3 = [(-8 1/3 )] 5 = (-2) 5 = -32. 13. ( ) . 29 2 3 23 1 4 35 3 325 16 6 ⋅⋅ = = = 14. 3 1/3 2 1/3 3 4/3 3 2 1/3 2/3 3 4 3( 23) 3 2 33 (2 3 ) 2 3 18 = = 3 . 15. 4 4 2 2 ( xy + + =+ 2 ) . 1 6 . ab a b 65 323 96 15 11 . 1 Preliminaries 42
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17. 16 81 2 3 2 3 2 3 5 4 5 4 45 1 4 1 4 54 14 14 14 14 54 xy z xyz z xyz xyz x z == () . / / /// = 18. (2 x 3 )(-3 x -2 )( 1 6 12 x / ) = - x 1/2 . 19. 3 4 3 2 3 4 3 2 4 3 3 2 16 27 9 6 2 3 2 3 2 3 2 2 3 3 2 2 3 3 49 23 7 xy xy x y x y x x y y x yx xy F H G I K J F H G I K J = F H G I K J F H G I K J = F H G I K J F H G I K J ( 8 ) . 20. 51 0 2 451 0 2 2 333 81 9 (3 )(3 ) x y x y x y = 661 21 / 3 224 24 (3 ) 3 9 . x y x = y 21. -2 π 2 r 3 + 100 π r 2 = -2 π r 2 ( π r - 50).
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This note was uploaded on 03/08/2012 for the course MATH 1010 taught by Professor Mihai during the Fall '08 term at UOIT.

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CR1 - CHAPTER 1, REVIEW EXERCISES, page 47 1. Adding x to...

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