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HW 1 - 1/2.5 pointsNotesQuestion ZumChemP6 14.E.010 What...

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1. –/2.5 points Notes Question: ZumChemP6 14.E.010. What hybridization is required for central atoms that have the following  arrangement of electron pairs? a tetrahedral arrangement of electron pairs a trigonal planar arrangement of electron pairs a linear arrangement of electron pairs How many unhybridized  p  atomic orbitals are present when a central atom  exhibits the following geometry? tetrahedral <INPUT TYPE=\ text NAME= RB_1208421_0_3_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON HTMLDirect  trigonal planar <INPUT TYPE=\ text NAME= RB_1208421_0_4_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON HTMLDirect  linear <INPUT TYPE=\ text NAME= RB_1208421_0_5_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON
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HTMLDirect  What are the unhybridized  p  atomic orbitals used for? The unhybridized  p  atomic orbitals are used to form <SELECT NAME=\ RC_1208421_0_6_1209969 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect   bonds. 2. –/1.5 points Notes Question: ZumChemP6 14.E.012. The atoms in a single bond can rotate about the internuclear axis without  breaking the bond. The atoms in a double bond and triple bond cannot  rotate about the internuclear axis unless the bond is broken. Why? The  p  orbitals must be parallel to each other to form the <SELECT NAME=\ RC_864036_1_0_865584 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect   bond.  If we try to rotate the atoms in a <SELECT NAME=\ RC_864036_1_1_865584 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect   bond, the  p  orbitals would no longer have the correct alignment necessary  to overlap.  Because <SELECT NAME=\ RC_864036_1_2_865584 >†<OPTION VALUE="">---Select---</OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect   bonds are present in double and triple bonds the atoms in a double or  triple bond cannot rotate (unless the bond is broken). 3. –/3 points Notes Question: ZumChemP6 14.E.018. Give the expected hybridization of the central atom for the following 
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molecules. (a)  PCl 5 (b)  ICl 3 (c)  SeCl 6   4. –/4.5 points Notes Question: ZumChemP6 14.E.020. Predict the hybrid orbitals used by the sulfur atom(s) in each of the  following. Also, predict the molecular structure, including bond angle(s). <INPUT TYPE=\ radio NAME= RC_826090_3_0_8 27638 VALUE= 0 > MACROBUTTON HTMLDirect square  planar<INPUT TYPE=\ radio NAME= RC_826090_3_0_8 27638 VALUE= 1 > MACROBUTTON HTMLDirect trigonal  pyramidal    <INPUT TYPE=\ radio NAME= RC_826090_3_0_8 27638 VALUE= 2 > MACROBUTTON HTMLDirect trigonal  planar<INPUT TYPE=\ radio NAME= RC_826090_3_0_8 27638 VALUE= 3 > (b) SF 2   <INPUT TYPE=\ radio NAME= RC_826090_3_3_827 638 VALUE= 0 > MACROBUTTON HTMLDirect see- saw<INPUT TYPE=\
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