HW 1 - 1 –/2.5 points Notes Question ZumChemP6 14.E.010 What hybridization is required for central atoms that have the following arrangement of

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Unformatted text preview: 1. –/2.5 points Notes Question: ZumChemP6 14.E.010. What hybridization is required for central atoms that have the following arrangement of electron pairs? a tetrahedral arrangement of electron pairs a trigonal planar arrangement of electron pairs a linear arrangement of electron pairs How many unhybridized p atomic orbitals are present when a central atom exhibits the following geometry? tetrahedral <INPUT TYPE=\ text NAME= RB_1208421_0_3_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON HTMLDirect trigonal planar <INPUT TYPE=\ text NAME= RB_1208421_0_4_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON HTMLDirect linear <INPUT TYPE=\ text NAME= RB_1208421_0_5_1 209969 VALUE= SIZE= 12 DIR= > MACROBUTTON HTMLDirect What are the unhybridized p atomic orbitals used for? The unhybridized p atomic orbitals are used to form <SELECT NAME=\ RC_1208421_0_6_1209969 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect bonds. 2. –/1.5 points Notes Question: ZumChemP6 14.E.012. The atoms in a single bond can rotate about the internuclear axis without breaking the bond. The atoms in a double bond and triple bond cannot rotate about the internuclear axis unless the bond is broken. Why? The p orbitals must be parallel to each other to form the <SELECT NAME=\ RC_864036_1_0_865584 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect bond. If we try to rotate the atoms in a <SELECT NAME=\ RC_864036_1_1_865584 >†<OPTION VALUE="">---Select--- </OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect bond, the p orbitals would no longer have the correct alignment necessary to overlap. Because <SELECT NAME=\ RC_864036_1_2_865584 >†<OPTION VALUE="">---Select---</OPTION>†<OPTION VALUE="0">pi</OPTION>†<OPTION VALUE="1">sigma</OPTION></SELECT> MACROBUTTON HTMLDirect bonds are present in double and triple bonds the atoms in a double or triple bond cannot rotate (unless the bond is broken). 3. –/3 points Notes Question: ZumChemP6 14.E.018. Give the expected hybridization of the central atom for the following molecules. (a) PCl 5 (b) ICl 3 (c) SeCl 6 4. –/4.5 points Notes Question: ZumChemP6 14.E.020. Predict the hybrid orbitals used by the sulfur atom(s) in each of the following. Also, predict the molecular structure, including bond angle(s)....
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This note was uploaded on 03/08/2012 for the course CHEM 162 taught by Professor N. during the Spring '08 term at University of Washington.

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HW 1 - 1 –/2.5 points Notes Question ZumChemP6 14.E.010 What hybridization is required for central atoms that have the following arrangement of

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