problem04_10

University Physics with Modern Physics with Mastering Physics (11th Edition)

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4.10: a) The acceleration is 2 s) (5.00 ) m 0 . 11 ( 2 2 s / m 88 . 0 2 2 = = = t x a . The mass is then kg. 9 . 90 2 m/s 0.88 N 0 . 80 = = = a F m b) The speed at the end of the first 5.00 seconds is m/s 4 . 4 = at , and the block on the
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Unformatted text preview: frictionless surface will continue to move at this speed, so it will move another m . 22 = vt in the next 5.00 s....
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