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# 2 d d w by me u wi 3 q2 4 0 d q d

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Unformatted text preview: d W (by me) U Wi 3 Q2 4 0 d Q d . >2 Q 3 Q2 4 0 d W2 1 Q2 4 0 d . ( " 27 " W3 1 Q2 4 0 d 1 Q2 4 0 d 2 Q2 4 0 d , F ' +: \$ \$ C Q2 1 1 4 0d Q2 1 1 4 0d Q2 1 2 4 0d Q2 1 2 4 0d " 3 -Q \$ ; U U U d d W by me U Wi 1 Q2 4 0 d U . ( . ( . ( 29 1 Q . >2 W2 d Q 1 Q2 4 0 d 2 " " " 1 Q2 4 0 d W3 1 Q2 4 0 d 1 Q2 4 0 d 2 Q2 4 0 d ( A B C D 31 - ( % LET'S DO THE CALCULATION !! 34 9 7 0 ' 7> + 0 ' ; q X=0 -2q X=d C \$ " \$ 7 >2 ' 7 7 I C x A) B) C) D) 0 1 2 3 37 H 7 0 \$ \$ ' ; " \$ q X=0 -2q X=d x A) B) C) D) E) A&B A&C B&C B&D A&D J 0 3 40 < \$ r q X=0 d ( \$ -2q X=d 0 x U 1 Qq 4 0 r 1 4 0 2Qq r d Set U = 0 1 r 2 r d Makes Sense! Q is twice as far from -2q as it is from +q 2 r 43 d \$ r q X=0 ( d-r \$ -2q X=d 3 x Setting U = 0 1 r 2 d r 2r d r r d 3 46 Makes Sense! Q is twice as far from -2q as it is from +q For a pair of charges: Just evaluate U q1q2 k r r q1 q2 (We usually choose U = 0 to be where the charges are far apart) For a collection of charges: Sum up U q1q2 k r for all pairs...
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