# Lect08 - \$" \$& \$ \$ 1 1 1 1 \$ 0 3 3 \$ 0 2 Q V 3 3 5 \$...

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Unformatted text preview: \$ + ! ) " # \$ & \$ ' \$ ( % ! . 1 1) 1 ) ) 1 + . . , \$ /' ' 0 * ) ) 3 3 ) \$ ( ' ) % ( ) / ( ) 0 ( 2 Q ( ! ( ! ) V 3 3 5 ) ( \$ ' % ) ) 6 ) ) 6 ( 6 = + 4 8 . : 6 ) ) 6 ( 6 = 6 ) 6 ) 7 8 . C ' ) 6 ) 6 ) ) Same ' ( ) 9 \$ - * Which of the following is NOT necessarily true: 50 +0 0 0 0 1 ) : ) ) ) * * ( * A circuit consists of three unequal capacitors C1, C2, and C3 which are connected to a battery of voltage V0. The capacitance of C2 is twice that of C1. The capacitance of C3 is three times that of C1. The capacitors obtain charges Q1, Q2, and Q3. - * X Compare Q1, Q2, and Q3. A. Q1 > Q3 > Q2 B. Q1 > Q2 > Q3 C. Q1 > Q2 = Q3 D. Q1 = Q2 = Q3 E. Q1 < Q2 = Q3 X < \$\$ ) */ *> * 0 ' < <= . % 1 1 C23 C2 1 C3 & < 1 2C1 1 3C1 5 6C1 C23 6 C1 5 Q1 Q23 C1V0 Q2 Q3 C23V0 6 C1V0 5 ; ? 9. . - \$ & ' \$ ( V ! A) 6 ) 6 )6 . % 6 @ ) 1 B C ?' % .6 ) V ) ) ) ) C ?' ) ) ) ) 6 6 ) 6 - 2 Two identical parallel plate capacitors are given the same charge Q, after which they are disconnected from the battery. After C2 has been charged and disconnected, it is filled with a dielectric. Compare the voltages of the two capacitors. B. V1 = V2 A. V1 > V2 C. V1 < V2 ' '' > B . % . .6 % . < ' < \$ < 1 =2 50 A D A1 \$ + 0 A1 ) A A) 6 0 A : A1 A 6A1 = A * - 2% Two identical parallel plate capacitors are given the same charge Q, after which they are disconnected from the battery. After C2 has been charged and disconnected, it is filled with a dielectric. Compare the potential energy stored by the two capacitors. B. U1 = U2 C. U1 < U2 A. U1 > U2 ' '' > 2 - 2 Two identical parallel plate capacitors are given the same charge Q, after which they are disconnected from the battery. After C2 has been charged and disconnected, it is filled with a dielectric. A. The charges will flow so that the charge on C1 will become equal to the charge on C2. B. The charges will flow so that the energy stored in C1 will become equal to the energy stored in C2. C. The charges will flow so that the potential difference across C1 will become the same as the potential difference across C2. D. No charges will flow. The charge on the capacitors will remain what it was before they were connected. \$ % \$ E E Q1 C1 A Q2 C2 1 C1V 2 2 1 C2V 2 2 Q1 C1 Q2 C2 U1 U2 U1 C1 U2 C2 4 1 5 F1 F162 & ! . F1 < F162 ' 1 '& 5 . % / 0 ' . < ' C 5 Q C V 8 > 8 /+ 0 / 0 . / 0 / 0 > /50 G 5 7 1 F1 F162 5 & ! . F1 < F162 ' 1 '& 5 . % / 0 ' . < ' C H H 5 5 . ' I ' ' \$ 8 > ' /50 ' D /+ 0 ' ) J / 0 ' : E E 9 5 & ! . F1 < F162 ' 1 '& 1 % F1 F162 5 . 8 / 0 ' . < ' > % . = 8 > /50 ? ) 1 /+ 0 ) *62 1 / 0 ) 26* ) 56 1 / 0 ) 62 1 <K 5 ) *6251 ) 1 ) 3/4 ( 0516 10 ) *62 1 5 & ! . F1 < F162 ' 1 1 '& 5 . 8 % F1 F162 / 0 ' . < ' = 8 > ) *62 > 1 /50 ) ? 1 /+ 0 <K ) *62 1 / 0 ' ) L/ ) 26* . 0516 10 1 / 0 ) ) 62 56 1 1 5 ) 6251 ) 1 ) 62 ; 5 & ! . F1 < F162 ' 1 '& 1 % F1 F162 5 . 8 / 0 ' . < ' > = 8 > ) *62 1 ) 62 1 /50 /+ 0 / 0 ) \$% ' ) ( ) 1 /*62 ( 62 0 1 5 & ! . F1 < F162 ' 1 '& 1 % F1 F162 5 . 8 / 0 ' . < ' > = ) *62 1 ) 62 1 ) 8 > 1 /*62 ( 62 0 C Q V Q VC '' 1 1 % \$ 5 & ! . F1 1 % '& < 62F1 ' % F1 62F1 5 . 8 & / 0 ' . < ' /50 \$ 8 . ' D . /+ 0 ' ) % / 0 ' : > / ' 0 ) ' 1 /*62 ( 62 0 ) 6 ) 6/*62 ( 62 0 '' 1 1 % \$ 5 & ! . F1 1 % '& % < / 0 '. F1 62F1 5 62F1 8 & . < ' ' > ' ) 6 ) 6/*62 ( 62 0 > = . . /50 A A)M \$ 6 /+ 0 A \$ / 0 A \$ A * ...
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