problem04_11

University Physics with Modern Physics with Mastering Physics (11th Edition)

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4.11: a) During the first 2.00 s, the acceleration of the puck is 2 m/s 563 . 1 / = m F (keeping an extra figure). At s 00 . 2 = t , the speed is m/s 13 . 3 = at and the position is m 13 . 3 2 / 2 / 2 = = vt at . b) The acceleration during this period is also 2 m/s 563 . 1 , and the speed at 7.00 s is m/s 6.26 s) 00 . 2 )( m/s
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Unformatted text preview: (1.563 m/s 13 . 3 2 = + . The position at s 00 . 5 = t is m 125 s) 2.00 s m/s)(5.00 (3.13 m 13 . 3 =-+ = x , and at s 00 . 7 = t is m, 21.89 s) )(2.00 m/s 3 (1/2)(1.56 s) m/s)(2.00 (3.13 m 12.5 2 2 = + + or 21.9 m to three places....
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