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Unformatted text preview: (5.976 X 10^19 particles /year) X (1 yr / 365 d ) X (1 d / 24 h) X (1 h / 3600 s) =1.89 X 10^12 particles / second So, the answer is : 1.89 X 10^12 particles / second 9./ The standard equation for a problem involving velocity and distance is v = d / t (v = velocity; d = distance; t = time ) => t = d / v; where v = 400 km /s and d = 5900 X 10^6 km. t = (5900 X 10^6 km) / (400 km /s) = 1.475 X 10^7 sec (1.475 X 10^7 sec) X (1 hr / 3600 s ) X (1 d / 24 h ) X (1 y / 365 d )=0.46 years = 5.6 months Chapter 17: 1./ 6400 km= 6,400,000 meters 6,400,000 meters=6,400,000,000 mm 6,400,000,000/ 3= 213,333,333 years ago. 5./ The speed of light is 299,792 km/s. Distance from Earth to Venus is 41,400,000 km. Divide the speed into the distance to get the time for a one way trip in seconds: 41,400,000/299,792=138.1 seconds. Round trip is: 138.1 X 2=276.2 seconds.= 4 min, 36 s The answer is 4 minutes, 36 seconds....
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This note was uploaded on 03/15/2012 for the course ASTR C100 taught by Professor K.ostrowski during the Fall '11 term at Coastline Community College.
 Fall '11
 K.Ostrowski
 Astronomy

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