Solutions_4

Solutions_4 - EE 310 Problem Set No. 4 Solutions 3.42 (a)...

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EE 310 Problem Set No. 4 Solutions 3.42 (a) ( ) ( ) ( ) ( ) ( ) 2 2 5 52 12 K 0.25 2 0.035 0.25 15 1.2 2.18 V 2 5 2.18 11.3 K 0.25 2.18 2 4.18 V D DD DQ p D SG TP SG SG SS SD V RR I k W I VV L V −− = = ⇒=  = +   = = = −− = 3.46 (a) Transistors matched 5 . 2 2 1 = = GS GS V V V, 5 . 2 = O V V ( )( ) 938 . 7 4 . 0 5 . 2 30 2 12 . 0 2 = = D I mA (c) 2 1 D D I I = ( )( ) ( )( ) 2 2 2 1 4 . 0 30 4 . 0 15 = GS GS V V ( ) 4 . 0 5 4 . 0 7071 . 0 1 1 = GS GS V V Which yields 86 . 2 1 = GS V V, 14 . 2 2 = = O GS V V V ( )( ) 45 . 5 4 . 0 86 . 2 15 2 12 . 0 2 = = D I mA
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EE 310 Problem Set No. 4 Solutions 3.47 (a) 5 . 2 3 1 = = GS V V V ( ) 69 . 3 6 . 0 5 . 2 2 12 . 0 8 . 0 3 2 3 = = L W L W 5 . 3 5 . 2 6 2 2 1 2 2 = + = + = = GS GS GS V V V V V V ( ) 59 . 1 6 . 0 5 . 3 2 12 . 0 8 . 0 2 2 2 = = L W L W 3 6 9 9 2 1 = = = V V GS V ( ) 31 . 2 6 . 0 3 2 12 . 0 8 . 0 1 2 1 = = L W L W 3.48 L M in saturation, D M in nonsaturation DL DD I I = ( )( ) ( ) [ ] ( )( ) 2 2 6 . 0 15 . 0 5 2 2 15 . 0 15 . 0 6 .
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Solutions_4 - EE 310 Problem Set No. 4 Solutions 3.42 (a)...

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