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Unformatted text preview: box delivers power to the circuit and must be a battery, whose voltage we will call V box . We get the following three equations, then, for the three unknowns I fan , V box , I right : (note that we define V box to be the voltage gain from the right to the left side of the box, define I right as moving CCW in the right-hand portion of the circuit, and define I fan as going downward.) I left + I right = I fan 6 V = V box- I right R-I right V box + I right 2 R = -6 W We can rewrite the third equation as I right * ( V box- I right R ) = 6 W. Whats in the parentheses, though, is just the right-hand side of the second equation! Therefore, the equation becomes I right * 6 V = 6 W, which means I right = +1 A. This lets us solve everything else, so we get: a) I fan = 4 Amps, moving downward b) The box contains a battery of V box = 8 V, oriented so that its positive terminal is on the left-hand side of the box....
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- Spring '07