Preparation for Test 2-solutions - Preparation for Test II...

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Unformatted text preview: Preparation for Test II Problem#1 a)H : p 1 =p 2 =p 3 =1/3 H A : At least one p i differs from its hypothesized value N=434 E(n1)=n p 1 =1/3 434=144,67 E(n2)=n p 2 =1/3 434=144,67 E(n3)=n p 3 =1/3 434=144,67 735 , 87 67 , 144 ) 67 , 144 81 ( 67 , 144 ) 67 , 144 119 ( 67 , 144 ) 67 , 144 234 ( ) ( )) ( ( 2 2 2 2 2 =- +- +- =- = ni e ni E ni Rejection region: For =0,01 and df=k-1=2 is 21 , 9 01 , 2 = Reject H 0 if 01 , 2 2 87,735>9m21 Opinions are not evenly divided b) n p p p p f f f pf f ) 1 ( 96 , 1 96 , 1- = Where f p =234/434=0,5391 =0,5391 0469 , 5391 , 434 5391 , 1 ( 5391 , 96 , 1 =- Problem #2 Ho: 1 p =0.32 2 p =0.50 3 p =0.18 H : At least one of probabilities differs from their hypothesized values. a) E( 1 n )=85x0.32=27.2 E( 2 n )=85x0.50=42.5 E( 3 n )=85x0.18=15.3 [ ] ) ( ) ( 2 2 i i i n E n E n x- = ( 29 ( 29 ( 29 3 . 15 3 . 15 17 5 . 42 5 . 42 32 2 . 27 5 . 27 36 2 2 2 2- +- +- = x =5.630 df=n-1=3-1=2 05 . = 99 . 5 2 = x , Rejection region ( 29 + ; 99 . 5 Since observed 2 x statistics does not fall into rejection region, we cannot reject Ho with...
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Preparation for Test 2-solutions - Preparation for Test II...

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