Lecture_18_notes - Chemical Engineering 374 Fluid Mechanics...

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1 1 Chemical Engineering 374 Fluid Mechanics Fall 2011 Minor Losses Recap Δ P à f, Re, f = f(Re, ε /D) Relate, Δ P, L, D, v. Colbrook Eqn. gives f(Re, ε /D) Implicit equation Haaland is explicit 3 problem types: Δ P, D, flow rate (v) Swamee & Jain relations Note: 2 friction factors Darcy (our book) Fanning = ¼ Darcy Moody Diagram plots the Colbrook Equation f drops with Re Transition region in grey Turbulent f >> laminar f Curves flatten, become independent of Re at high Re (fully rough flow) 2
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2 • Write – SS, no Heat transfer, no Shaft work – Mechanical losses due to friction • Pipes Pipelines consist of more than just pipes Valves, fittings, bends, elbows, flow meters, expansions, etc. All cause losses Generally small (hence minor losses) Provided have long pipes and few fittings Two methods to account for losses Loss Coefficient: K L Equivalent Pipe Length 3 Δ P ρ + Δ v 2 2 + g Δ z = - F F = fLv 2 2 D Loss Coefficient Δ P ρ + Δ v 2 2 + g Δ z = - F = - K v 2 2 = - W L 3 forms: Energy, pressure, head Constant times: Kinetic energy
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