This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Math 1012: QRMS Name: Quiz 2 Feb. 17, 2012 2B 65 Suppose that a fuelefficient German car travels an average of 26 kilometers on 1 liter of gasoline. If gasoline costs 1.50 euros per liter, how much will it cost to drive 300 kilometers? Solution: We have the quantities: 26 km/L, 1.5 /L, 300 km To get the desired units of euros () we can combine the units as follows: km km L L = km L km L = . Doing the same computation with the numbers gives: Total cost = (300 km) 26 km L 1.5 L = 17.31 Optionally we could convert this to dollars by applying the appropriate conversion factor (found in the text): 17.31 $1.256 1 = $21.74 3B 60 In 2007, Walmart had profits of $12.7 billion. Exress this profit in terms of dollars per minute. Solution: We currently have a number with units of $/year. To get to units of $/min we just need to apply conversion factors: $12.7 109 yr & & 1& yr & 365 day 1 day & 24 & hr
& 1& hr 60 min = $24, 162.86/min 1 Math 1012: QRMS Quiz 2 Feb. 17, 2012 3A 81 Your total cost for dinner in a restaurant after the tip was $76.40. Assuming you left a 20% tip, what was the bill for food and taxes? Solution: The bill increased by 20% to a new value of $76.40. Then we have bill + (20% bill) = $76.40 bill + 20 bill 100 bill 1 + 20 100 bill 120 100 bill = $76.40 bill = $63.67 Alternatively we could use the fact that an increase of 20% is the same thing as saying the new value is 120% of the old: bill 120% = $76.40 bill 120 100 = $76.40 100 120 = $76.40 = $76.40 = $76.40 and then follow the same steps from there. 2 ...
View
Full
Document
This note was uploaded on 03/12/2012 for the course MATH 150 taught by Professor A during the Spring '05 term at University of Arizona Tucson.
 Spring '05
 A
 Math

Click to edit the document details