algebrasheet1 solutions

algebrasheet1 solutions - Algebra practice Directions: Name...

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Unformatted text preview: Algebra practice Directions: Name Show all work on a separate piece of paper. Place your final answer on this sheet. 3 x — l a. Evaluate and simplify completely 1. Given g(x): 1) g<—2) = - u) go) = —- no go) = Undefimlw) gm) = v) g(x + 3) =-——— i 3 I )<+2 b. Solve algebraically for exact x i) g(x)=5 ii) g(x+2)=4 iii) g(x)+2=4 x : l x : c—n -—-—' X = .52.— 2. Simply the gfference quotient for the follo W wing functions [different quotient h a) f(x)=x2+2x+3 ———.——f(x+h)_f(x)= ZX+Z+iA 1. b) f(x)=x3—5 W: c) f(x)= L‘. Zx+h) i We) ... x X 3. Simplify the following completely with a common denominator. Your final answer will not contain any negative exponents. a a) £_5x+2_ 3x +§X+Z x—l 2x C l+2t =7+i+f )m+2«/IT (H3)Vz an3n+l _ ’5 g) 3nan+l— T i) (x3 +1)2 —6x3(x3 +1)= -- i (x3 +1)4 (X3+‘)3 2x-(x2 +5)” —x2(x2 +5)% -2x = I O x k) ____._,————— 1) ————=..____...———- x2+5 (X1+5)%_ h XL(X+$,\)1 m) E‘i=_z.>< n) s = 3 y—? xv?) fi—l (Li’x)(x 4. Solve algebraically for the exact solution(s). Solve for the indicated variable. Assume all other variables TQOhwicqlbl M? Shiv \ are const ts. it». ‘ I) “— x=i €5X+esx=l x: 14—63624]? x... Za+b x=_;-_5_ 10g(x)+10g(x—21)=2 x: 3+2£=1 x x = \ u—H (p-1)(p2-11) O ” —J—’— (p—2>(p+3) 2 ¢ 2!; = y3 ln(t+2)—ln(t) =1n(7) ' (7-va3 y=_5_"L_EL xzy—x3=2(2y+3) *av3 x: 3(ax+1)—2x=4(a-ax) x: “‘6 or2(x+1)(x+3)=15 ID x = A log(x) —log(x~ 1) =1 1 5x5 —% Z: 9 Cir—'7 or0=4z3+6z2—24z—36 mm t2—t—6=14 t: 0 or-S IOte3’+212e3’ =0 5 (i1) t=J~ 3‘ =12(.8)‘ x: W52 x—l—1022 1'6 x: (3—x)3=—l3 x = 9xe‘“ —3x2e“" = 0 x = ’ e . ln(ln(x)) = l I» 5‘. x = ‘ A(.83)" = B(b)* x: S or “'3 (x—4)(x+2)=7 3 x: / 4xeX—3e‘ =0 2 y = /!E 5—5::72 = O 1‘4y+2=0 l+2y 7 r: *7 2t—(3t+4)=5(t+2) y = N9 jolui'lm 3—3X —C«Ax FL“; x2+2—xy=y+3 y=IAx+By+C=O 1. r: Zor'2t3—16t“=0 t: f—i ln(t+2)—ln(t)=ln(7r) 2 ab p=iQLy33p+—p7_2=0 R=_p_fl_“—" %=l+% P— a 5. Determine if each statement is Correct or Incorrect. Circle the correct answer. x+3 C©Vx2+121=x+11 c©JZ=i2 . ©1 %=x:3 w+1 © 4:1 for W¢—1 ©I ln(exey)=x+y © el"("‘)+5=)ce5 w+1 2 ln(M) l (G +. C©l M —1 B = I 1 2—1 2"-‘=2"+2y n( ) n() 11103) © Tl(\/Z) 2n(a) C®log(ab’)= tlog(ab) C(I) ln(e" +e")= x+ y r3 — 64 = r—4 -1 2 @x x x x ©I 8(2t+1)3=(4t+2)3 ©I (ex)2=ezx @I 1 = _1 x—4 4—x C©ln(l)=e oi —1—=<z-s>-% o ab 3(Z_8)2 a +1) a+b 2 C6 1 :1; @I 10g(x):ln(x) C©flzAx+B x+2 x 2 log(t) ln(t) x C©log(x+ y) = log(x)10g(y) C©e4mm = 4x C@] + y)3 2 1+ y3 C®If f(x) =5”,then f(x+4)=5* +4 V O |?—‘ H A b.) N i 4; ©I (x+l)2+2(x+1)=(x+l)(x+3 ...
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This note was uploaded on 03/12/2012 for the course ACCOUNTING 202 taught by Professor B during the Spring '10 term at Arizona.

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algebrasheet1 solutions - Algebra practice Directions: Name...

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