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Quiz - It rs View Attempt 1 of 1 0 Title S t a r te d Time...

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It rs View Attempt 1 of 1 0 Title: 5r{1-Qo1 Started: June 5, 2008 3:45 PM Submitted: 5, 2008 3:49 PM Time oo:04:01 spent: - Total L8/20 = 90% ' totut score adjusted by 0. 0 i Maximum possible score: score: 20 1. Please note that this is the only question based on the illustrated problem using RET1YR (#2. 31 in the text; please refer to the text/output, if required). Suppose we wanted to test 'Is the mutual funds' mean return different from that of S&P 500" at same 5% significance level, what would the outcome be? . . (Hint: a two-tailed test) Student Correct Response Answer Feedback A. The mean mutual fund returns are same as (as good as) that of the s&P 500 B. This requires the computed test statistic, which is not given.

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-\ ! 2. returns are different from that of s&P 500 D. The mean mutual fund better (hieher than the S&p 500's) E. The mean worse (lower than the S&P General ITe reject the belief that mean are equal Feedback: to those of S&p b00, which is _lg% (i. e., a loss of 18%), as the computed z is 2.48. Score: 2/2 with anv data (as that for RETIYR or Hr{yMpG used in this assignment), which of the folrowing does NOT represent a measure of location? Student Correct ResPonse Answer Feedback A. Mode ffi Variance ffi B. C. Mean I I'i:*'
l. Feedback: Score: (location). Variance is a of the data. 2/2 measure of the spread (2. 30) the best 3. Questions 3 through g use the nileage data Based on the sample data given in CARS2, what is estimate of the true mean mileage? Student Response Correct Answer A. 29 B. 27.5 ffi zs. rs C. D. 28 E. 6.53 General Assuming z-statistic could dala, what is the criticai be used in the test of the CARS2 value (Table- value) ? Feedback M 4. A. ffi B. I T.2I 1. 645 1tQ & IF q.rt is the

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5. E. 1.96 General At 5% significance, the critical value of z is Feedback: 1.645 (Note this is also the value used to construct the 90% CI, essentially leaving 5% chance in the rieht tail. ) Score:. 2/2 What is the computed value of the test statistic for the hypothesis test on the true mean hishway mileage suggested in the assignment? Student Correct Response Ansrer Feedback A. 5.2 B. 2.45 c. 1.645 D. 1.96 S t.z 6 E. General This is (28.15 - 27.5) /0.54 = I.2 Feedback: Score: IYhat is the lower bound of the 95% CI for the true mean highway mi leage? Response Ansver A. 29.21 6.
D. 28.57 ffi zt.oa tr General This is mean - half Feedback: 28. l5-1.07) = 27.08 Score: 2/2 Assume the 90% CI for will imply that we can true mean is more than the mean HIIYMPG is 27.2 to 29. Thrs be at least "' % confident that the 27. t. ffi 7. Student Response A. 100% gsst B. c. 90% D. 97.5% E. 80% General Feedback: Score: Correct Answer ffi Feedback The chance the true mean is 27.2 fo 29 is 90% implies that there is 5% chance it is above 29 (with 5% chance being below 27.2). So, the chance it is over 27.1 should be at least 95%. Given this data, if you have to make a statement such as "f am very confident that the true mean mileage is less than "' (value) ", which of the following will you choose for the specific value? 8.

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Student Correct Response Answer Feedback A. 23 B. 26 c. 27.5 D. 29 &gz w E. General In this case, we should be most comfortable Feedback: picking the highest value in the list (all other ranges are contained in its range). Score: 2/2 The
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Quiz - It rs View Attempt 1 of 1 0 Title S t a r te d Time...

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