This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Math 113 Homework 3 Solutions 1. Fraleigh, section 6, exercise 32 (as always, carefully justify your answers): Mark each of the following true or false. a. Every cyclic group is abelian. True: any cyclic group has a generator a , and a m a n = a m + n = a n a m (see also Theorem 6.1 in Fraleigh). b. Every abelian group is cyclic. False: the Klein 4group is abelian but not cyclic. c. ( Q , +) is a cyclic group. False. Indeed, the subgroup ( a ) generated by an element a Q consists of all integer multiples of a . When a = 0, we get ( a ) = { } ; when a negationslash = 0, the subgroup ( a ) does not contain a 2 Q . So in all cases ( a ) is a proper subgroup of Q , hence Q is not cyclic (it is not generated by one of its elements). d. Every element of every cyclic group generates the group. False, for example 2 Z 4 does not generate Z 4 . Another example: for n 2 the element 0 does not generate Z n . e. There is at least one abelian group of every finite order &gt; . True: for any integer n &gt; 0, ( Z n , +) is an abelian group of order n . f. Every group of order 4 is cyclic. False: the Klein 4group is not cyclic. g. All generators of Z 20 are prime numbers. False: 9 is a generator of Z 20 , but 9 isnt prime. Since we have defined Z 20 to be a set of congruence classes, the statement doesnt even quite make sense anyway, because being prime is a property of an integer, while being a generator of Z 20 is a property of a congruence class. (For example, 7 = 27 Z 20 , however the integer 7 is prime while 27 is not). In general you should be careful to distinguish between integers and their equivalence classes mod n whenever it is not clear from the context. h. If G and G are groups, then G G is a group. False. G and G might not intersect at all (if their elements had completely different names!); and even if they do intersect, G G may not have a welldefined binary operation on it. Namely, the group operations on G and G might not agree on G G : for instance how do you intersect ( R + , ) with ( Z , +)? So it doesnt even make sense to ask whether G G is a group. i. If H and K are subgroups of a group G , then H K is a group. True, by section 5 exercise 54 (cf. homework 2). j. Every cyclic group of order &gt; 2 has at least two distinct generators. True. Any finite cyclic group of order n &gt; 2 is isomorphic to Z n , where both 1 and 1 are generators (distinct since we assumed that n &gt; 2; for most n there are other generators too). Any infinite cyclic group is isomorphic to Z , which also has two distinct generators, namely 1 and 1. 2. Fraleigh, section 6, exercises 44 and 56(a)....
View
Full
Document
This note was uploaded on 03/14/2012 for the course MATH 113 taught by Professor Ogus during the Spring '08 term at Berkeley.
 Spring '08
 OGUS
 Math

Click to edit the document details