6 - if the number of moles of gaseous products exceeds the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
, where ∆n represents the change in the number of moles of gas in the reaction (moles gaseous products - moles gaseous reactants). When ∆n is zero (no change in number of moles of gas), the term (RT) ∆n equals 1 and Kc = Kp. When ∆n is not zero, meaning that there is a change in the number of moles of gas in the reaction, then Kc ≠ Kp. 17.26 a) Since ∆n = number of moles gaseous products - number of moles gaseous reactants, ∆n is a positive integer. If ∆n is a positive integer, then (RT) -∆n is less than 1. Thus, Kp must be larger since it is multiplied by a fraction that is less than 1 gives Kc . Kc is smaller than Kp. b) Assuming that RT > 1 (which occurs when T > 12.2 K, because 0.0821 x 12.2 = 1), Kp > Kc
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: if the number of moles of gaseous products exceeds the number of moles of gaseous reactants. Kp < Kc when the number of moles of gaseous reactants exceeds the number of moles of gaseous product. 17.27 a) Number of moles of gaseous reactants = 0; Number of moles of gaseous products = 3; ∆n = 3 - 0 = 3 b) Number of moles of gaseous reactants = 1; Number of moles of gaseous products = 0; ∆n = 0 - 1 = -1 c) Number of moles of gaseous reactants = 0; Number of moles of gaseous products = 3; ∆n = 3 - 0 = 3 17.28 a) ∆ngas = 1 b) ∆ngas...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online