CIVL_112_HW5

# CIVL_112_HW5 - Problem 6.30:30 Hull Problem 6.52 A = 217th...

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Unformatted text preview: Problem 6.30 :30 Hull Problem 6.52 A = 217th 6.30 The built—up timber beam is subjccicd lo a vertical shear ol' 5 kN. Knowing that the allnwahle shearing force in the mils is 300 N1 determine the huge“ pcrmissilﬂe spacing .x' M the nails. I, : 351311? + Aid“ 7 IEBMWF ink—9‘5) cm 31' 3251—26933- Mn": J; 2 \$191": : ﬁcﬁﬂzﬁ}; L— 657!)qu {:7 fix-My: I = LII”; = IQWETIM‘? wit Q: Ql : Ali, : = 25‘bcr-aa liking at : v_o.. I sews—74w ‘- _ FHAJP _ _ Fran" \$5 5- —-—‘% - 7'43, - 4.3.1 In») = I‘ll/min. 6.52 (:1) Determine the shearing stress at point P of a thin-walled pipe of the cross section shown caused by a verﬁeal shear V. (b) Show that the maximum shearing stress occurs for I9= 90° and is equal to ZVIA, whercA is the cross-sectional area of me pip-e. J: Ar: = gyms: I=éJ=1W§z 'FW 0‘- C-L‘Mﬂtpaﬁ arc. v ﬁrm 6 w w; z: ' Framer-n 653 6.53 and 6.54 An extruded beam has aunifonn wall thickness :. Deummgby thw vmical shear and bra! the emotional am (if the Imam Empress Illﬁ mmimum shearinastresaas EM=KWA3 and dtlﬁmiue themnsmkfareachaftlw two orientations shown. 1,:(0116‘): : Jar-:1“? I: HE)" = gift I = 21, + L111= éa‘t at = Matt-3]: ﬁ-a‘t 9-2: (£1111?) = wha‘t Q: Gaza; = ~\$~aft EELQ _ Vii-5‘55"” _ _ 545 v '3'" Law gaatxzn' ' a of: BT‘Eﬁ: : ii _ .1 g V lﬁat_9\$éE-%% =%K*k% :- kﬁ k:%:2.2\$ a kraﬁ = 2.1:: an pm,“ 555 ‘55 Fara imam m: of two orrmm- mm'ala mammal-em manh- m— emicim shnw that Eq. {'15} _ Q I” - H main vniid pro-Vim than bulb Q and I an; mputed by using the mfamnd secljnn ufthc beam {see 561:1 4.15} 3.11:1 provided further ﬁnal r is Ill: germ] widﬂ-l of Il'le lawn whurc TM. is mum-ad. LE} ER; Le a. rte-Farean modulus LILL-I a’E dark-1H? E ' -E. E ﬂ “var:- wane-+£- El 1: wrth I: 0? animal, seoﬁ‘an m H—nzb—"d MHP'HEJPI'PFI by n": +9 aL‘hﬁﬂ He Ac’ruaf Truns¥orm€rl +Mns armed suffer-1. THE Lunch“: SEL‘HM SELTFOH sire-v.55 alis‘l'ribu‘l'l‘au 'm 'H-H: cross I Sari-fan {5 jinn by G: : 5%};— wL-crt I fa Hue max-new} a‘F £u£r+m gF "Ht-e +mHs-FMMEJ Cir-335 accﬂ'a‘w and? J! I: mans-Jud 'qun "Hue can-Irma a‘F 'Hn: Wan5+|MMEJ seal-(an- TLc Llofﬁ'zan'ia} alreaer ME 01ft!" ﬁx i=- AH hum? AA = 55—“?! 4A a mlmgnj JA 2 aid"? {1: Shara”: 1'- m:m£n“| a? +H":l Vlﬁ‘rﬂrﬂ'hlﬂ‘i SEL+FEM - r A” .- 15 '3- -_- ER 5L2“ H's-u . a. I? In: f I c} is alfrl‘ribu‘hci we» at‘l'UtP w;th Ed 'Hlus I’ = —g'-. «f = 1'33. It ...
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## This note was uploaded on 03/15/2012 for the course CIVL 000 taught by Professor Kk during the Spring '10 term at HKUST.

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CIVL_112_HW5 - Problem 6.30:30 Hull Problem 6.52 A = 217th...

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