YF_ISM_17

YF_ISM_17 - TEMPERATURE AND HEAT 17 17.1. IDENTIFY and SET...

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17-1 T EMPERATURE AND H EAT 17.1. IDENTIFY and SET UP: 9 FC 5 32 TT =+ °. EXECUTE: (a) F (9/5)( 62.8) 32 81.0 F T = += ° (b) F (9/5)(56.7) 32 134.1 F T = ° (c) F (9/5)(31.1) 32 88.0 F T = ° EVALUATE: Fahrenheit degrees are smaller than Celsius degrees, so it takes more F° than C° to express the difference of a temperature from the ice point. 17.2. IDENTIFY and SET UP: 5 CF 9 (3 2 ) = ° EXECUTE: (a) C (5/9)(41.0 32) 5.0 C T = (b) C (5/9)(107 32) 41.7 C T = (c) C (5/9)( 18 32) 27.8 C T = −− = ° EVALUATE: Fahrenheit degrees are smaller than Celsius degrees, so it takes more F° than C° to express the difference of a temperature from the ice point. 17.3. IDENTIFY: Convert each temperature from °C to °F. SET UP: 9 5 32 C ° EXECUTE: 18 C ° equals 9 5 (18 ) 32 64 F °° ° and 39 C ° equals 9 5 (39 ) 32 102 F. °° ° The temperature increase is 102 F 64 F 38 F = ° . EVALUATE: The temperature increase is 21 C°, and this corresponds to 9 5 F (21 C ) 38 F 1 C ⎛⎞ = ⎜⎟ ⎝⎠ ° . ° 17.4. IDENTIFY: Convert 10 K T Δ = to F °. SET UP: 9 5 1 K F . EXECUTE: A temperature increase of 10 K corresponds to an increase of 18 F°. Beaker B has the higher temperature. EVALUATE: Kelvin and Celsius degrees are the same size. Fahrenheit degrees are smaller, so it takes more of them to express a given T Δ value. 17.5. IDENTIFY: Convert T Δ in kelvins to C° and to F°. SET UP: 9 5 F == EXECUTE: (a) () 99 55 10.0 C 18.0 F Δ = Δ = °= ° (b) CK 10.0 C Δ = Δ = ° EVALUATE: Kelvin and Celsius degrees are the same size. Fahrenheit degrees are smaller, so it takes more of them to express a given T Δ value. 17.6. IDENTIFY: Convert T Δ between different scales. SET UP: T Δ is the same on the Celsius and Kelvin scales. 180 F 100 C = , so 9 5 F = . EXECUTE: (a) 49.0 F T Δ = °. 9 5 (49.0 F ) 27.2 C F T Δ ° . ° (b) 100 F T Δ = °. 9 5 ( 100.0 F ) 55.6 C F T Δ = = ° ° EVALUATE: The magnitude of the temperature change is larger in F° than in C°. 17
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17-2 Chapter 17 17.7. IDENTIFY: Convert T in °C to °F. SET UP: 9 FC 5 (3 2 ) TT =+ ° EXECUTE: (a) 9 F 5 (40.2 ) 32 104.4 F. T = °° ° Yes, you should be concerned. (b) 99 55 ( 32) (12C ) 32 54F . =+= + = °°° ° EVALUATE: In doing the temperature conversion we account for both the size of the degrees and the different zero points on the two temperature scales. 17.8. IDENTIFY: Set CF = and FK . = SET UP: 9 5 32 C ° and 5 KC F 9 273.15 ( 32 ) 273.15 T = + ° EXECUTE: (a) TTT == gives 9 5 32 ° and 40 ; T = ° 40 C 40 F. = (b) gives 5 9 ( 32 ) 273.15 = + ° and () 95 49 (32 ) 273.15 575 ; T = += 575 F 575 K. = ° EVALUATE: Since 273.15 there is no temperature at which Celsius and Kelvin thermometers agree. 17.9. IDENTIFY: Convert to the Celsius scale and then to the Kelvin scale. SET UP: Combining Eq.(17.2) and Eq.(17.3), 5 KF 9 32 273.15, = °+ EXECUTE: Substitution of the given Fahrenheit temperatures gives (a) 216.5 K (b) 325.9 K (c) 205.4 K EVALUATE: All temperatures on the Kelvin scale are positive. 17.10. IDENTIFY: Convert K T to C T and then convert C T to F . T SET UP: 273.15 and 9 5 32 °. EXECUTE: (a) C 400 273.15 127 C, T = F (9/5)(126.85) 32 260 F T = ° (b) C 95 273.15 178 C, T = = ° F (9/5)( 178.15) 32 289 F T = ° (c) 77 C 1.55 10 273.15 1.55 10 C, T ° F (9/5)(1.55 10 ) 32 2.79 10 F T + = × ° EVALUATE: All temperatures on the Kelvin scale are positive.
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This note was uploaded on 03/14/2012 for the course MAE 162D taught by Professor Shaefer during the Spring '11 term at UCLA.

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YF_ISM_17 - TEMPERATURE AND HEAT 17 17.1. IDENTIFY and SET...

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