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Homework2 - Name M612 Last'rst Homework H a hormone binds...

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Unformatted text preview: Name M612? Last, 'rst Homework H, a hormone, binds to receptor R with a dissociation constant, KH, of 4 x 10‘7 M. (The RH complex then triggers some biochemical process, such as cAMP formation but this is not relevant to the present problem.) D, a drug, binds to the receptor with a dissociation constant, KD, of 6 x 10-6 M. The D site is distinct from the H site so that both D and H can occupy the receptor simultaneously. Thus, D can also bind to the RH complex; H can also bind to the RD complex. (The RDH complex, however, is unable to trigger cAMP formation.) The dissociation constant for the RH + D reaction is 5 x 10‘7 M. 1. Draw all the equilibrium reactions of the "linked" functions described above. 0 D ms 11‘ M» RD + RDH xx“ 2. Calculate the constant for the dissociation of H from RDH. MW: ( lock) . <4x(o*?‘)<5x(cr7> 2 (Q W) “M ~13 42,3101 ~» 04 KH ‘ é K1047 (continued) 7/“, K M‘- ffll: 04K” 3. 4 _ [NEH] _ EHJLDJ 1. LPJLDJL/i] LP‘ " ‘ MD ‘ “K01?” y XD/ E01?) 2 1‘- J , '. I} T i x I + % 4 ‘7};— + Calculate the fractions (i.e., proportions, percentages) of each R species (R, RH, RD, etc.) when: 3- [H]=4x10'7Mand[D]=o. ‘1 v‘ (:03 '2 0/ Wrctbre [RD] 0L [RD/7’ +11%}va 4a: m 4x116 su‘ ' i (51'qu {6' 117" (a! 1’0"”! V, 1‘, $5] (73¢ [L Dl=6x10-6M. , I ___——-l-—__—- - / : 2 Mlvflfi‘SWY ' IWS . (1, Increasing the concentration of D at any fixed free [H] will N‘Cfggficc the binding of H. (write “increase” or “decrease”) 4 KH/ Wash/1; 1)}an may/“C fijflw Ciidc‘ D Is [Marv]. ...
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