Homework3key

# Homework3key - The equation used for these lines is...

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Unformatted text preview: The equation used for these lines is: V: (Vmax,f[S])/(Ks(1 + ([P]/Kp)) + [3]) Sample values for Kp/Ks = 0.01 [S] [P] Vmax Ks 0 25 1 1 24 1 2 23 1 3 22 1 4 21 1 ' 5 20 1 6 19 1 7 18 1 8 17 1 9 16 1 10 15 1 11 14 1 12 13 1 13 12 1 14 11 1 15 10 1 16 9 1 17 8 1 18 7 1 19 6 1 20 5 1 21 4 1 22 3 1 23 2 1 24 1 1 25 0 1 Part b) HHHHHHHHHHHHHHHHHHHHHHHHHH 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 0.01 V 0 0.00041632 0.000868432 0.001361 162 0.001900238 0.002492522 0.003146303 0.003871681 0.0046811 0.005590062 0.006618134 0.007790368 0.009139375 0.010708402 0.012556054 0.01476378 0.017448201 0.020782396 0.025034771 0.030645161 0.038387716 0.049763033 0.0681 1 1455 0.102678571 0.192 0.961538462 The plot for Kp/Ks = 1 shows a linear increase in v as [S] increases. Therefore, when Kp = Ks , v increases in a linear fashion for this model. Part c) An enzyme that responds as an "on-off switch" is one that is essentially “off” (v=0) until the substrate concentration reaches a certain level, at which time it turns "on" (v=Vmax). The condition from our plots that best ﬁts this description is KP/Ks = 0.01. When Kp << Ks, free enzyme binds to P much more tightly than to S, accounting for the “on-off switch" response. [S] ...
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## This note was uploaded on 03/16/2012 for the course MCB MCB 123 taught by Professor Christopherfraser during the Spring '11 term at UC Davis.

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Homework3key - The equation used for these lines is...

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