HW!0 - Chapter 10 - Quality Control 3. a. n = 20 A2 = 0.18...

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Chapter 10 - Quality Control 10-1 3. a. n = 20 A 2 = 0.18 = X = 3.10 Mean Chart: = X ± A 2 R = 3.1 ± 0.18(0.45) D 3 = 0.41 R = 3.1 ± .081 = 0.45 D 4 = 1.59 Hence, UCL is 3.181 and LCL is 3.019. All means are within these limits. Range Chart: UCL is D 4 R = 1.59(0.45) = .7155 LCL is D 3 R = 0.41(0.45) = .1845 In control since all points are within these limits. 9. 100 ) 946 (. 054 . 96 . 1 054 . n ) p 1 ( p z p are limits Control 054 . ) 100 ( 16 87 ns observatio of number total defectives of number total p ± = ± = = = . 044 . 054 . ± = Hence, UCL = 0.10 LCL = 0.01 Note that observations must be converted to fraction defective, or control limits must be converted to number of defectives. In the latter case, the upper control limit would be 10 defectives and the lower control limit would be 1 defective. Even though all points are within these limits, the process appears to be out of control because 75% of the values are above 4%. 23.
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HW!0 - Chapter 10 - Quality Control 3. a. n = 20 A2 = 0.18...

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