04BIS1012012RecombinLect4b

2 2 0 observed progeny types e expected progeny types

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Unformatted text preview: ion, R.L. Rodriguez 2012 48 (0 - E) E Chi-square test for linkage Calculating 2 for all 4 progeny types, assuming independent assortment or a 1:1:1:1 ratio. With 2205 total progeny, independent assortment would produce an expected ratio of: 551 : 551 : 551 : 551 (22054) 2 = ( 0 - E 1 )2 (0 - E2)2 (0 - E 3 )2 (0 - E 4 )2 + + + E1 E2 E3 E4 BC 551 bc 551 Bc 551 bC 551 (770 - 551)2 (716 - 551)2 (401 - 551)2 (318 - 551)2 + + + 2 = 2 = 87.0 + 49.4 + 40.8 + 98.5 = 276.5 March 19, 2012 BIS101001, Spring 2012--Genes and Gene Expression, R.L. Rodriguez 2012 49 Another Method for Calculating 2 (0 - E)2 E (O - E)2 47961 27225 22500 54289 (O - E)2 E 87.0 49.4 40.8 98.5 2 = 276.5 2 = Class BC bc Bc bC O 770 716 401 318 2205 E* 551 551 551 551 March 19, 2012 BIS101001, Spring 2012--Genes and Gene Expression, R.L. Rodriguez 2012 50 Interpreting the Chi-square Test of Linkage 2 value of 276.5, a table is used that relates the 2 values to the probability (p) that the deviations between the observed and expected progen...
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