eqns test 2

# eqns test 2 - 0.0683 slug(= 2.2 lb = 1 kg 3.28 ft = 1 m...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 0.0683 slug (= 2.2 lb) = 1 kg 3.28 ft = 1 m 0.224 lb (= 0.102 kg) = 1 N T S = 59 o F = 15 o C = 519 o R = 288 o K 1.8 o R = 1.0 o K ( _ ) o R = ( _ ) o F + 460 ( _ ) o K = ( _ ) o C + 273 p S = 2116 lb/ft 2 = 1.013 x 10 5 N/m 2 = 1 atm ρ s = 0.002378 lb sec 2 /ft 4 = 1.225 kg/m 3 a s = 1116 ft/s = 340 m/s T(h) = 15 - .0065h (T in o C, h in meters) R air =1716 ft lb/(slug o R)=287 N m/(kg o K) γ air = 1.4 μ s = 3.7373 x 10-7 lb sec/ft 2 = 1.7894 x 10-5 kg/(m sec) c p, air = 6006 ft lb/(slug o R) = 1004 N m/(kg o K) p c R 1 γ = γ - F ma = & & F = GMm/R 2 G = 6.67 x 10-11 m 3 /(kg s 2 ) g o = 32.2 ft/s 2 = 9.81 m/s 2 p = ρ RT dp = - ρ g dh G dp = - ρ g o dh p 2- p 1 = - ρ g (h 2- h 1 ) ρ AV = m ¡ = constant dp = - ρ VdV M = V/a a 2 = γ RT q = ρ V 2 / 2 2 2 1 2 1 2 V V p p p q p = constant 2 2 ρ ρ + = + = + = 1 g (h h ) RT 1 p e p-- = g aR 1 1 p T ( ) p T- = E G E G R h ( )h R h = + 1 2 2 2 1 1 1 p T p T γ γ γ- & ¡ & ¡ ρ = = ¢ £ ¢ £ ρ ¤ ¥ ¤ ¥ 2 2 1 2 p 1 p 2 p...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online