Exam 1 equation sheet

# Exam 1 equation sheet - 0.0683 slug (= 2.2 lbm) = 1 kg 1.8...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 0.0683 slug (= 2.2 lbm) = 1 kg 1.8 R = 1.0 K o o 3.281 ft = 1 m ( _ ) R = ( _ ) F + 460 o o 0.224 lb (= 0.102 kgf) = 1 N ( _ ) K = ( _ ) C + 273 TS = 59oF = 15oC = 519oR = 288oK o o pS = 2116 lb/ft2 = 1.013 x 105 N/m2 = 1 atm = 0.002378 lb sec /ft = 1.225 kg/m s - g0 (h - h1 ) p = e RT p1 2 4 3 p T 0 = ( ) aR p1 T1 Rair = 1716 ft lb/(slug oR) = 287 N m/(kg oK) -g h=( RE )h G R E + hG R -1 2 as = 1116 ft/s = 340 m/s air = 1.4 cp = cp, air = 6006 ft lb/(slug oR) = 1004 N m/(kg oK) T(h) = 15 - .0065h (T in oC, h in meters) go = 32.2 ft/s2 = 9.81 m/s2 G = 6.67 x 10 -11 F = ma M=V/a F = GMm/R m /(kg s ) 3 2 a2 = RT dp = -g dhG dp = -go dh AV = m = constant p2 - p1 = - g (h2 - h1) dp = -VdV p = RT p1 + V12 V 2 = p 2 + 2 = constant 2 2 q V 2 2 -1 c p T1 + V V = c p T2 + = c p T0 2 2 2 1 2 2 T0 -1 2 = 1+ M1 T1 2 2 1 - + 2 M1 +1 p2 = 2 p1 1 T = 2 T1 p 02 p1 = ( + 1) M 2 4 M1 - 2( - 1) 2 2 1 -1 dA dV = (M 2 - 1) A V A At 2 1 2 -1 2 = 2 1+ M M +1 2 +1 -1 ...
View Full Document

## This note was uploaded on 03/19/2012 for the course AERO 201 taught by Professor Strganac during the Fall '05 term at Texas A&M.

Ask a homework question - tutors are online