Exam 1 equation sheet

Exam 1 equation sheet - 0.0683 slug (= 2.2 lbm) = 1 kg 1.8...

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Unformatted text preview: 0.0683 slug (= 2.2 lbm) = 1 kg 1.8 R = 1.0 K o o 3.281 ft = 1 m ( _ ) R = ( _ ) F + 460 o o 0.224 lb (= 0.102 kgf) = 1 N ( _ ) K = ( _ ) C + 273 TS = 59oF = 15oC = 519oR = 288oK o o pS = 2116 lb/ft2 = 1.013 x 105 N/m2 = 1 atm = 0.002378 lb sec /ft = 1.225 kg/m s - g0 (h - h1 ) p = e RT p1 2 4 3 p T 0 = ( ) aR p1 T1 Rair = 1716 ft lb/(slug oR) = 287 N m/(kg oK) -g h=( RE )h G R E + hG R -1 2 as = 1116 ft/s = 340 m/s air = 1.4 cp = cp, air = 6006 ft lb/(slug oR) = 1004 N m/(kg oK) T(h) = 15 - .0065h (T in oC, h in meters) go = 32.2 ft/s2 = 9.81 m/s2 G = 6.67 x 10 -11 F = ma M=V/a F = GMm/R m /(kg s ) 3 2 a2 = RT dp = -g dhG dp = -go dh AV = m = constant p2 - p1 = - g (h2 - h1) dp = -VdV p = RT p1 + V12 V 2 = p 2 + 2 = constant 2 2 q V 2 2 -1 c p T1 + V V = c p T2 + = c p T0 2 2 2 1 2 2 T0 -1 2 = 1+ M1 T1 2 2 1 - + 2 M1 +1 p2 = 2 p1 1 T = 2 T1 p 02 p1 = ( + 1) M 2 4 M1 - 2( - 1) 2 2 1 -1 dA dV = (M 2 - 1) A V A At 2 1 2 -1 2 = 2 1+ M M +1 2 +1 -1 ...
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This note was uploaded on 03/19/2012 for the course AERO 201 taught by Professor Strganac during the Fall '05 term at Texas A&M.

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